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Q:

A school has four sections A, B, C, D of Class IX students.

1. If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context?

A. Half yearly examinations were more difficult.

B. Annual examinations were more difficult.

C. Both the examinations had almost the same difficulty level.

D. The two examinations cannot be compared for difficulty level.

 

2. How many students are there in Class IX in the school?

 A. 336                      B.189                       C. 335                         D. 430

 

3. Which section has the maximum pass percentage in at least one of the two examinations?

  A. A Section            B. B Section            C. C Section               D. D Section

 

4. Which section has the maximum success rate in annual examination?

 A. A Section             B. B Section            C. C Section               D. D Section

 

5. Which section has the minimum failure rate in half yearly examination?

 A. A section             B. B section             C. C section               D. D section

 

Half yearly examinations were more difficult.
If the number of students passing an examination be considered a criteria for comparision of difficulty level of two examinations, which of the following statements is true in this context? - See more at: https://www.theonlinetestcentre.com/table-charts7.html#sthash.slrcbjro.dpuf

Answer

1. ANSWER : C 


 Explanation -  Number of students who passed half-yearly exams in the school 


= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)
= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)

= 288.

Also, Number of students who passed annual exams in the school

= (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)

= 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.

Thus Statements (a), (b) and (d) are false and Statement (c) is true. 


 


 2. ANSWER : D 


 Explanation -  Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class: 


 = (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430. 


 


 3. ANSWER : D 


 ExplanationPass percentages in at least one of the two examinations for different sections are:


  For Section A = 14+6+6428+14+6+64×100 = 84112×100% = 75%


 For Section B =12+17+5523+12+17+55×100  % = 78.5%


 For Section C = 8+9+4617+8+9+46×100%= 78.75%


 For Section D = 13+15+7627+13+15+76×100%= 79.39%


  Clearly ,the pass percentage is maximum for Section D 


 


  


 4. ANSWER : A


 Explanation - Total number of students passed in annual exams in a section 


= [ (No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams) ] in that section


 Success rate in annual exams in Section A= 14+64112 × 100% = 69.64%


 Similarly, success rate in annual exams in:


 Section B = 12+55107×100% =  62.62% 


 Section C = 8+4680×100% = 67.5% 


 Section D = 89131×100% = 67.94% 


 Clearly, the success rate in annual examination is maximum for Section A. 


 


  


 5. ANSWER : D 


 Explanation - Total number of failures in half-yearly exams in a section


  = [ (Number of students failed in both exams) + (Number of students failed in half-yearly but passed in Annual exams) ] in that section


 Failure rate in half-yearly exams in Section A %= 37.5 %


 Similarly, failure rate in half-yearly exams in:


  Section B = 32.71%


  Section C = 31.25%


  Section D = 30.53%


  Clearly, the failure rate is minimum for Section D.


 = (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)


 = (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76)


 = 288.


 


 Also, Number of students who passed annual exams in the school


 = (Number of students failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)


 = (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76)


 = 288.


 


Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level.


Thus Statements (a), (b) and (d) are false and Statement (c) is true.

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Subject: Table Charts Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

Q:

The following chart represents the number of students who passed the CAT exam or the XAT exam or the CET exam or None of these exams. (Assume that there are no students who passed more than one exam.)

             Number of students who qualified CAT/XAT/CET Exams

1.  Which year showed the best result in MBA entrance exams (in terms of percentage of students who cleared) ?

1. 2000               2. 2001               3. 2002               4. Cannot be determined

 

2. What was the percentage of students who succeeded in at least one of three exams in 2000 ?

1. 82.4%             2. 82.8%             3. 82.35%           4. 83.3%

 

3. What is the percentage increase in the number of students in 2002 over 2000 ?

1. 30%                 2. 17.64%           3. 117.6%           4. 85%

 

4. What is the percentage of students who cleared CAT in 2000 ?

1. 19.56%           2. 12.65%           3. 14.28%           4. 11.76%

 

Answer

1. ANSWER : 2  


Explanation -  Compare the respective pass percentage for three years : 2000, 2001 and 2002   


= (140 x 100)/170 < (150 x 100)/180 and (150 x 100)/180 > (160 x 100)/200


 = 82.35% < 83.33% and 83.33% > 80%


 


 


2. ANSWER : 3  


Explanation -  Total percentage of students who succeeded in at least one of three exams in 2000 = (140 x 100)/170= 82.35 %   


 


 


3. ANSWER : 2  


Explanation -  Total percentage increase in the number of students in 2002 over 2000 is = (30 x 100)/170 =17.64 %  


 


 


4. ANSWER : 4  


Explanation -  Total percentage of students who cleared CAT in 2000 =(20 x 100)/170 = 11.76 %

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Subject: Bar Charts

Q:

The following pie chart shows the amount of subscriptions generated for India Bonds from different categories of investors.

1. In the corporate sector, approximately how many degrees should be there in the central angle ?

A. 120                 B. 121                 C. 122                 D. 123


2. If the investment by NRI's are Rs 4,000 crore, then the investments by corporate houses and FII's tog ether is:

A. 24,000 cr       B. 24,363 cr       C. 25,423 cr       D. 25,643 cr


3. What percentage of the total investment is coming from FII's and NRI's ?

A. 33%                B. 11%                C. 44%                D. 22%


4. If the total investment other than by FII and corporate houses is Rs 335,000 crore, then the investment by NRI's and Offshore funds will be (approximately) ?

A. 274,100         B. 285,600         C. 293,000         D. Cannot be determined


5. If the total investment flows from FII's were to be doubled in the next year and the investment flows from all other sources had remained constant at their existing levels for this year, then what would be the proportion of FII investment in the total investment into India Bonds next year (in US $ millions) ?

A. 40%                B. 50%                C. 60%                D. 70%

Answer

1. ANSWER :   C 


Explanation -   34 x 3.6 = 122.4 (since 1% = 3.6 degrees)  


  


2. ANSWER :  B 


Explanation -   (67/11) x 4000 = 24 363.6364   


 


3. ANSWER :  C


Explanation -  (33 + 11) = 44 


 


4. ANSWER :  A


Explanation -  Investment other than NRI and corporate houses is 33% = 335000.  Also, investment by offshore funds and NRI's is equal to 27%.


 Hence, (27 x 335000)/33 = 274 090.909


 


5. ANSWER : B


Explanation -  FII's currently account for 33 out of 100.


If their value is doubled and all other investments are kept constant then their new value would be 66 out of 133 = approximately equal to 50%

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Subject: Pie Charts

Q:

What is CTS and what do you know about it?

Answer

The Change and Transport System (CTS) is a tool that helps you to organize development projects in the ABAP Workbench and in Customizing, and then transport the changes between the SAP Systems and clients in your system landscape. This documentation provides you with an overview of how to manage changes with the CTS and essential information on setting up your system and client landscape and deciding on a transport strategy. Read and follow this documentation when planning your development project.

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Subject: ABAP

Q:

Refer to the exhibit. Which statement describes DLCI 17?

A: DLCI 17 describes the ISDN circuit between R2 and R3.
B: DLCI 17 describes a PVC on R2. It cannot be used on R3 or R1.
C: DLCI 17 is the Layer 2 address used by R2 to describe a PVCto R3.
D: DLCI 17 describes the dial-up circuit from R2 and R3 to the service provider.

Answer

Answer : C


Explanation:


Virtual circuits (VC)s are identified by DLCIs. DLCI values typically are assigned by the Frame Relay service provider. Frame Relay DLCIs have local significance.  A DLCI identifies a VC to the equipment at an endpoint. A DLCI has no significance beyond the single link. Two devices connected by a VC may use a different DLCI value to refer to the same connection.


Virtual circuits (VC)s are identified by DLCIs. DLCI values typically are assigned by the Frame Relay service provider. Frame Relay DLCIs have local significance.  A DLCI identifies a VC to the equipment at an endpoint. A DLCI has no significance beyond the single link. Two devices connected by a VC may use a different DLCI value to refer to the same connection. - See more at: https://www.orbitco-ccna-pastquestions.com/CCNA-Past-Questions%3A-WAN.php#sthash.nWKdjylM.dpuf
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Subject: CCNA

Q:

A default Frame Relay WAN is classified as what type of physicalnetwork?

A: broadcast point-to-multi point
B: broadcast multi-access
C: non broadcast multi-access
D: non broadcast multi-point

Answer

Answer : C


Explanation:


FrameRelay, ATM, and X.25 are non-broadcast multiple access (NBMA) networks. NBMA networks allow only data transfer from one computer to another over a VC or across a switching device. NBMA networks do not support multicast or broadcast traffic


FrameRelay, ATM, and X.25 are non-broadcast multiple access (NBMA) networks. NBMA networks allow only data transfer from one computer to another over a VC or across a switching device. NBMA networks do not support multicast or broadcast traffic - See more at: https://www.orbitco-ccna-pastquestions.com/CCNA-Past-Questions%3A-WAN.php#sthash.hb05ZKYs.dpuf
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Subject: CCNA

Q:

What is a Non-PO Invoice?

Answer

A non-po is an invoice which does not have po(purchase order).However, these invoices requires approval for authorized person/persons to process for payment.


What_is_a_Non-PO_Invoice1558075538.jpg image

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Subject: Accounts Payable Exam Prep: Bank Exams
Job Role: Bank Clerk , Bank PO

Q:

What procedure for excess payment to supplier I would like know without adjusting invoice that means how supplier will send back excess amount how do in oracle apps?

Answer

Excess payment to supplier is treated as Advance paid to supplier. This will show as debit balance in supplier account.

Supplier can send the payment by way of cheque / demand draft without adjusting in his subsequent bills.

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Subject: Accounts Payable