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Q:

If the positions of the first and the fifth digits of the number 14278359 are interchanged, similarly the positions of the second and the sixth digits are interchanged and so on, then which of the following will be the second digit from the right end after the rearrangement ?

A) 5 B) 2
C) 7 D) 4
 
Answer & Explanation Answer: B) 2

Explanation:

Given number is 14278359
As given 1st and 5th digits, 2nd & 6th, 3rd & 7th and 4th & 8th digits are to to be interchanged.
Therfore, the rearranged number is 83591427
Then, the second digit from the right end is 2.

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Filed Under: Arithmetical Reasoning
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Q:

The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8,748, its purchase price was ?

A) Rs.14,000 B) Rs.12,000
C) Rs. 12,800 D) Rs. 15,000
 
Answer & Explanation Answer: B) Rs.12,000

Explanation:

We have P = 8748, R = -10 and n = 3
Therefore, the purchase price of the machine
= P1+R100n= 87481-101003
= 8748 x (100/90) x (100/90) x (100/90)
= 12,000.

 

Therefore, the purchase price of the machine was Rs. 12,000.

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Filed Under: Percentage
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Q:

If the given two numbers are respectively 7% and 28% of a third number, then what percentage is the first of the second ?

A) 24% B) 29%
C) 34% D) 25%
 
Answer & Explanation Answer: D) 25%

Explanation:

Here, k = 7 and l = 28
Therefore, first number = klx100 % of second number = 7/28 x 100% of second number = 25% of second number.

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Q:

If HCF of two numbers is 8,which of the following can never be their LCM?

A) 32 B) 48
C) 60 D) 152
 
Answer & Explanation Answer: C) 60

Explanation:

60 is not a multiple of 8

 

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Filed Under: HCF and LCM
Exam Prep: Bank Exams

Q:

John sells his laptop to Mark at a loss of 20% who subsequently sells it to Kevin at a profit of 25%. Kevin after finding some defect in the laptop, returns it to Mark but could recover only Rs.4.50 for every Rs. 5 he had paid. Find the amount of Kevin’s loss if John had paid Rs. 1,75,000 for the laptop ?

A) Rs.16,500 B) Rs.17,500
C) Rs.14,200 D) Rs.15,520
 
Answer & Explanation Answer: B) Rs.17,500

Explanation:

Let’s assume John bought the laptop for Rs. 100
He then sells it to Mark at a loss of 20% => Rs. 80,
Who consequently sells it to Kevin at a profit of 25% =>  Rs. 100
Then, Kevin sells it back to Mark for Rs. 90 (Rs.4.50 for every Rs. 5 that he had paid initially), so he suffers a loss of Rs. 10
Therefore, for Rs. 100 there is a loss of Rs. 10,
Then for Rs. 1,75,000 there will be a loss of Rs. 17,500.

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Filed Under: Profit and Loss
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Q:

If watches bought at prices ranging from Rs. 200 to Rs. 350 are sold at prices ranging from Rs. 300 to Rs. 425. What is the greatest possible profit that might be made in selling nine watches ?

A) Rs. 1800 B) Rs. 2000
C) Rs. 2025 D) Rs. 1750
 
Answer & Explanation Answer: C) Rs. 2025

Explanation:

Profit would be maximum if watches are brought for Rs. 200 and sold for Rs. 425
Profit = Rs. (425 - 200) = Rs. 225
Profit of 9 watches = Rs. 225 x 9 = Rs.2,025.

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Q:

A sweet seller sells 3/5th part of sweets at a profit of 10% and remaining at a loss of 5%. If the total profit is Rs 1500, then what is the total cost price of sweets ?

A) Rs.37,500 B) Rs.36,400
C) Rs.37,415 D) Rs.36,500
 
Answer & Explanation Answer: A) Rs.37,500

Explanation:

Assume A be the cost price.

 

Therefore,
35×A×10100 - 25×A×5100 = 1500

 

=>  A = Rs 37,500.

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Q:

Vishal invested 10% more than Trishul. Trishul invested 10% less than Raghu. If the total sum of their investments is Rs. 5780, how much amount did Raghu invest ?

A) Rs.2010 B) Rs.2200
C) Rs.2000 D) Rs.2100
 
Answer & Explanation Answer: C) Rs.2000

Explanation:

Let money invested by Raghu = Rs. x
Money invested by Trishul = 9/10 x = 0.9x
Money invested by Vishal = 9/10x * 110/100 = 0.99x
Also, x+0.9x+0.99x = 5780
= x= 5780/2.89 = 2000

Therefore, amount invested by Raghu is Rs. 2000.

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Filed Under: Partnership
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