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Q:

Which of the following does not contain the material particles

A) alpha - rays	B) beta - rays
C) gamma - rays	D) anode rays

Answer & Explanation Answer: C) gamma - rays

Explanation:

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Filed Under: Chemistry

Q:

At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but,not together?

A) (5 + 5/11 )min past 7	B) (6 + 5/11) min past 7
C) 7	D) 8

Answer & Explanation Answer: A) (5 + 5/11 )min past 7

Explanation:

When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.
At 7 o'clock, they are 25 min. spaces apart.
$\therefore$ Minute hand will have to gain only 5 min. spaces.
55 min. spaces are gained in 60 min.

5 min spaces are gained in $(\frac{60}{55} * 5)$ min = $5 \frac{5}{11}$ min

so, Required time = $5 \frac{5}{11}$ min past 7

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A watch which gains 5 seconds in 3 minutes was set right at 7 a.m. In the afternoon of the same day, when the watch indicated quarter past 4 o'clock, the true time is:

A) 4pm	B) 5pm
C) 6pm	D) 7pm

Answer & Explanation Answer: A) 4pm

Explanation:

Time from 7 am to 4.15 pm = 9 hrs 15 min = $\frac{37}{4}$ hrs

3 min. 5 sec. of this clock = 3 min. of the correct clock.

Now 3min.5sec. is $\frac{37}{720}$ hrs of this clock = 3 min.is $\frac{1}{20}$ hrs of the correct clock

$\frac{37}{4}$ hrs of clock = $(\frac{1}{20} \times \frac{720}{37} \times \frac{37}{4})$ hrs of the correct clock.

= 9 hrs of the correct clock.

$\therefore$ The correct time is 9 hrs after 7 am. i.e., 4 pm.

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

A clock is started at noon. By 10 minutes past 5, the hour hand has turned through

A) 145	B) 155
C) 165	D) 175

Answer & Explanation Answer: B) 155

Explanation:

Angle traced by hour hand in 12 hrs = 360º

Angle traced by hour hand in 5 hrs 10 min. i.e $\frac{31}{6}$ hrs = ${(\frac{360}{12} \times \frac{31}{6})}^{0}$ = $155^{0}$

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together ?

A) 100/11 min past 8	B) 120/11 min past 8
C) 90/11 min past 8	D) 80/11 min past 8

Answer & Explanation Answer: B) 120/11 min past 8

Explanation:

In this type of problems the formulae is $(5 x - 30) \times \frac{12}{11}$
x is replaced by the first interval of given time Here i.e 8
$(5 * 8 - 30) * \frac{12}{11}$
= $\frac{120}{11}$ min

Therefore the hands will be in the same straight line but not
together at $\frac{120}{11}$ min.past 8.

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Filed Under: Clocks
Exam Prep: Bank Exams
Job Role: Bank PO

Q:

Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip?

A) 10	B) 8
C) 6	D) 4

Answer & Explanation Answer: B) 8

Explanation:

Amy can travel clockwise or anticlockwise on the diagram.

Clockwise, she has no choice of route from A to B, a choice of one out of two routes from B to C, and a choice of one out of two routes from C back to A. This gives four possible routes.

Similarly, anticlockwise she has four different routes.

Total routes = 8

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Filed Under: Time and Distance
Exam Prep: GRE

Q:

In a class of 78 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course?

A) 6	B) 12
C) 24	D) 18

Answer & Explanation Answer: C) 24

Explanation:

You could solve this by drawing a Venn diagram. A simpler way is to realize that you can subtract the number of students taking both languages from the numbers taking French to find the number taking only French. Likewise find those taking only German. Then we have:Total = only French + only German + both + neither

78 = (41-9) + (22-9) + 9 + neither.

Not enrolled students = 24

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Filed Under: Average
Exam Prep: GRE

Q:

A cubical block of metal weighs 6 pounds. How much will another cube of the same metal weigh if its sides are twice as long?

A) 48	B) 12
C) 36	D) 60

Answer & Explanation Answer: A) 48

Explanation:

If you double the sides of a cube, the ratio of the surface areas of the old and new cubes will be 1: 4. The ratio of the volumes of the old and new cubes will be 1: 8.

Weight is proportional to volume. So, If the first weighs 6 pounds, the second weighs 6x8 pounds =48.

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Filed Under: Ratios and Proportions
Exam Prep: GRE

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