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Q:

Singbhum is famous for 

A) Coal B) Copper
C) Iron D) Aluminium
 
Answer & Explanation Answer: C) Iron

Explanation:
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Filed Under: Indian Economy

Q:

What was the day of the week on 16th August, 1947?

A) Sunday B) Monday
C) Saturday D) Thursday
 
Answer & Explanation Answer: C) Saturday

Explanation:

15th August, 1947 = (1946 years + Period from 1st Jan., 1947 to 15th )

 

Counting of odd days:

 1600 years have 0 odd day. 300 years have 1 odd day.

 

 47 years = (11 leap years + 36 ordinary years)= [(11 x 2) + (36 x 1) ]odd days = 58 odd days = 2 odd days.

 

Jan  Feb  Mar  Apr  May  Jun  Jul  Aug.

31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 227 days = (32 weeks + 3 days) = 3,

 

Total number of odd days = (0 + 1 + 2 + 3) odd days = 6 odd days.

 

Hence, the required day was 'Saturday'.

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Filed Under: Calendar

Q:

What will be the day of the week 15th August, 2010?

A) Sunday B) Saturday
C) Wednesday D) Monday
 
Answer & Explanation Answer: A) Sunday

Explanation:

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

 

Odd days in 1600 years = 0

 

Odd days in 400 years = 0

 

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 = 4 odd days.

 

Jan. Feb. Mar.  Apr.  May.  Jun.  Jul.  Aug.

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days = (32 weeks + 3 days) = 3 odd days.

  

Total number of odd days = (0 + 0 + 4 + 3) = 7 =  0 odd days.

 

Given day is Sunday

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Filed Under: Calendar

Q:

What was the day on 15th august 1947 ?

A) Friday B) Saturday
C) Sunday D) Thursday
 
Answer & Explanation Answer: A) Friday

Explanation:

15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)

15th_August_1947_day1534219857.jpg image

 

Odd days in 1600 years = 0 

 

Odd days in 300 years = 1

 

46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day 

 

Jan.   Feb.   Mar.   Apr.   May.   Jun.   Jul.   Aug 

 

( 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 ) = 227 days = (32 weeks + 3 days) = 3 odd days.

 

Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days. 

 

 

Hence, as the number of odd days = 5 , given day is Friday.

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Filed Under: Calendar
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Q:

The calendar of the year 2024 can be used again in the year?

A) 2030 B) 2052
C) 2048 D) 2036
 
Answer & Explanation Answer: B) 2052

Explanation:

NOTE :

Repetition of leap year ===> Add +28 to the Given Year.

Repetition of non leap year

Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2.

Step 2:  Add +6 to the Given Year.

 

Solution : 

Given Year is 2024, Which is a leap year.

So, Add +28 to the given year (i.e 2024 + 28) = 2052

Therfore, The calendar of the year 2024 can be used again in the year 2052.

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Filed Under: Calendar

Q:

The calendar of the year 2006 was used before in the year?

A) 1990 B) 1995
C) 2002 D) 2000
 
Answer & Explanation Answer: B) 1995

Explanation:

 

Given year 2006, when divided by 4 leaves a remainder of 2.

NOTE: When remainder is 2, 11 is subtracted to the given year to get the result.

So, 2006 - 11 = 1995

 

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Filed Under: Calendar

Q:

Which calendar was used again in the year 1856?

A) 1828 B) 1850
C) 1830 D) 1852
 
Answer & Explanation Answer: A) 1828

Explanation:

Given year 1856, when divided by 4 leaves a remainder of 0.

NOTE: When remainder is 0, 28 is subtracted to the given year to get the result.

So, 1856 - 28 = 1828

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Filed Under: Calendar

Q:

The calendar of the year 1897 can be used again in the year?

A) 1908 B) 1901
C) 1903 D) 1926
 
Answer & Explanation Answer: C) 1903

Explanation:

NOTE :

Repetition of leap year ===> Add +28 to the Given Year.

Repetition of non leap year

Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2.

Step 2:  Add +6 to the Given Year.

 

Solution : 

Given Year is 1897, Which is a non leap year.

Step 1 : Add +11 to the given year (i.e 1897 + 11) = 1908, Which is a leap year. 

Step 2 : Add +6 to the given year (i.e 1897 + 6) = 1903

Therfore, The calendar of the year 1897 can be used again in the year 1903

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Filed Under: Calendar