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Q:

There are 44 students in a hostel, due to the administration, 15 new students has joined. The expense of the mess increase by Rs. 33 per day. While the average expenditure per head diminished by Rs. 3, what was the original expenditure of the mess ?

A) Rs. 404	B) Rs. 514
C) Rs. 340	D) Rs. 616

Answer & Explanation Answer: D) Rs. 616

Explanation:

Let the average expenditure per head be Rs. p
Now, the expenditure of the mess for old students is Rs. 44p
After joining of 15 more students, the average expenditure per head is decreased by Rs. 3 => p-3
Here, given the expenditure of the mess for (44+15 = 59) students is increased by Rs. 33
Therefore, 59(p-3) = 44p + 33
59p - 177 = 44p + 33
15p = 210
=> p = 14
Thus, the expenditure of the mess for old students is Rs. 44p = 44 x 14 = Rs. 616.

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Q:

Two boys and a girl can do a work in 5 days, while a boy and 2 girls can do it in 6 days. If the boy is paid at the rate of 28$ a week, what should be the wages of the girl a week ?

A) 24 $	B) 22 $
C) 16 $	D) 14 $

Answer & Explanation Answer: C) 16 $

Explanation:

Let the 1 day work of a boy=b and a girl=g, then
2b + g = 1/5 ---(i) and
b + 2g = 1/6 ---(ii)
On solving (i) & (ii), b=7/90, g=2/45
As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week,
so a girl will be paid $28 \times \frac{\frac{2}{45}}{\frac{7}{90}}$ = 16 $.

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Q:

Find the missing number in the given series ?

15, 51, 216, 1100, ?, 46452

A) 5660	B) 6560
C) 6750	D) 6630

Answer & Explanation Answer: D) 6630

Explanation:

Let first no. be "k" and multiple be "l"...start value of y with 3
then,
[(k x y) + {l x (l-1)}]
Thus, we get

15 x 3 + 3 x 2 = 51
51 x 4 + 4 x 3 = 216
216 x 5 + 5 x 4 = 1100
1100 x 6 + 6 x 5 = 6630
6630 x 7 + 7 x 6 = 46452

Therefore, the missing number is 6630.

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Q:

A student can divide her books into groups of 5, 9 and 13. what is the smallest possible number of the books ?

A) 487	B) 585
C) 635	D) 705

Answer & Explanation Answer: B) 585

Explanation:

The smallest possible number of books = L.C.M of 5, 9 and 13.
Therefore, L.C.M of 5,9 and 13 is = 5 x 9 x 13 = 585.

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Q:

What is the next number of the following sequence ?

21, 77, 165, 285, ......

A) 404	B) 415
C) 426	D) 437

Answer & Explanation Answer: D) 437

Explanation:

The series follow the rule,

21 = $5^{2}-4$
77 = $9^{2} - 4$
165 = $13^{2} - 4$
285 = $17^{2} - 4$

5,9,13,17,21,(+4)...
In the same way next no. will be
$21^{2} - 4$ = 441 - 4 = 437

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Q:

A constructor estimates that 4 people can paint Mr. Karthik's house in 6 days. If he uses 5 people instead of 4, how long will they take to complete the job ?

A) 3 days	B) 26/3 days
C) 13/4 days	D) 24/5 days

Answer & Explanation Answer: D) 24/5 days

Explanation:

we know that m1 x d1 = m2 x d2
=> 4 x 6 = 5 x d
where d = no. of days taken by 5 men to paint
d = 24/5 days.

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Q:

The average number of visitors of a library in the first 4 days of a week was 58. The average for the 2nd, 3rd, 4th and 5th days was 60.If the number of visitors on the 1st and 5th days were in the ratio 8 : 9. Then what is the number of visitors on the 5th day of the library ?

A) 54	B) 64
C) 68	D) 72

Answer & Explanation Answer: D) 72

Explanation:

If number of visitors on 1st, 2nd, 3rd, 4th & 5th day are k, l, m, n & o respectively, then
k + l + m + n = 58 x 4 = 232 ---- (i) &
l + m + n + o = 60 x 4 = 240 ---- (ii)
Subtracting (i) from (ii), we get
o-k = 8 ---(iii)
Given, k/o = 8/9 ----(iv)
So from (iii) & (iv), we get
a = 64, e = 72
Therefore, number of visitors on 5th day is 72.

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Q:

A man traveled from the village to the post-office at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village ?

A) 40 km	B) 30 km
C) 20 km	D) 10 km

Answer & Explanation Answer: C) 20 km

Explanation:

Average speed = $\frac{2 a b}{a + b}$ , here a=25 b=4
= 2 x 25 x 4/(25+4) = 200/29 km/hr.

Distance covered in 5 hours 48 minutes
= Speed x time = (200/29)x (29/5) Distance covered in 5 hours 48 minutes = 40kms.

Distance of the post office from the village = (40/2) = 20 km.

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