5
Q:

# If $3x+7=x2+p=7x+5$, what is the value of P ?

 A) 17/2 B) 25/3 C) 33/4 D) 41/5

Explanation:

$3x+7=7x+5=>7x-3x=2=>4x=2=>x=2$

Now, $3x+7=x2+p=32+7=14+p=>p=172$

Q:

64/12 in simplest form?

 A) 19/6 B) 32/4 C) 16/3 D) None of the above

Explanation:

64/12 = 16/3 in simplest form.

1 151
Q:

10+10(9) =

 A) 180 B) 110 C) 100 D) 19

Explanation:

According to BODMAS Rule,

10 + 10(9)

= 10 + 90

= 100

0 133
Q:

50.003% of 99.8÷49.988 = ?

 A) 2 B) 0 C) 1 D) 50

Explanation:

50.003% of 99.8 ÷ 49.988 = ?

? ~= (50 x 100/100)/50

? ~= (50 x 100)/(100 x 50)

? ~= 1

2 342
Q:

[15% of 300% of 560] × 2 ÷ 5 =

 A) 100 B) 90 C) 85 D) 105

Explanation:

[15% of 300% of 560] × 2 ÷ 5

= (15 x 300 x 560 x 2)/100 x 100 x 5

~= 100

2 430
Q:

Solve this inequality 3b - 7 < 32?

 A) b = 13 B) b < 13 C) b > = 13 D) b < = 13

Explanation:

The given 3b - 7 < 32 can be solved as

3b - 7 < 32

3b < 39

b < 13.

4 470
Q:

Solve this inequality 3p - 16 < 20?

 A) p >= 12 B) p <= 11/3 C) p < 12 D) p > 11/3

Explanation:

The given inequality is 3p - 16 < 20

For solving this inequality, follow these steps

Now add 16 on both sides

we get 3p - 16 + 16 < 20 + 16

=> 3p  < 36

Now divide the above eqn with 3 on both sides

we get, 3p/3 < 36/3

p < 12.

1 358
Q:

Two numbers are such that the sum of twice the first number and thrice the second number is 36 and the sum of thrice the first number and twice the second number is 39. Find the difference between the numbers?

 A) 15 B) 3 C) 9 D) 6

Explanation:

Let the required two numbers be a, b

From the given data,

2a + 3b = 36 .....(1)

3a + 2b = 39 .....(2)

Now, by solving 1 and 2 eqnts, we get

5a = 45

a = 9 ....(3)

Put (3) in (1), we get

2(9) + 3b = 36

=> 18 + 3b = 36

3b = 36 - 18

=> b = 18/3 = 6

Required, difference between the numbers = a + b = 9 + 6 = 15.

4 445
Q:

(P - 4)(P - 6)

Simplify the above?

(P - 4)(P - 6)

Now applying distributive property, we get

P.P - 4.P - 6.P + 6.4

P^2 - 10P + 24