20
Q:

# The total of 324 of 20 paise and 25 paise make a sum of Rs. 71. The no of 20 paise coins is :

 A) 50 B) 100 C) 150 D) 200

Explanation:

Let the number  of 20 paise coins be x. Then the no of 25 paise coins = (324 - x).

0.20 * (x) + 0.25 (324 - x) = 71 => x = 200..

Q:

Simplify the following expression:

$(32×16)+(53×72)-(134×43)=?$

 A) 1221 B) 2112 C) 3621 D) 4112

Explanation:

4 171
Q:

$(311×336)-(94×123)+(511×2210)$

 A) -92 B) -132 C) 132 D) 92

Explanation:

0 302
Q:

Express in meters the sum of 0.5035 km, 332.9 cm, and 1771mm:

 A) 500 B) 510 C) 508.6 D) 58.6

Explanation:

0 209
Q:

The value of $323÷1130of23-14of212÷35×44525of712÷34-34×112÷214$ is:

 A) 2\frac{6}{7} B) 2\frac{2}{9} C) 3\frac{4}{7} D) \frac{10}{21}

Explanation:

2 126
Q:

If $5sinθ=4$, then the value of $secθ+4cotθ4tanθ-5cosθ$ is:

 A) \frac{3}{2} B) 1 C) \frac{5}{4} D) 2

Explanation:

0 160
Q:

The value of $sec6θ-tan6θ-3sec2θtan2θ+1cos4θ-sin4θ+2sin2θ+2$ is:

 A) 3/4 B) 2/3 C) 1/2 D) 1

Explanation:

0 118
Q:

In triangle ABC, $∠C=90°$, AC = 5 cm  and BC = 12 cm. The bisector of $∠A$ meets BC at D. What is the length of AD?

 A) \frac{2}{3}\sqrt{13} cm B) \frac{4}{3}\sqrt{13} cm C) 2\sqrt{13} cm D) \frac{5\sqrt{13}}{3} cm

Explanation:

0 89
Q:

If , then what is the value of 3ab?

 A) \frac{3}{2} B) -3 C) -\frac{3}{2} D) 5