A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?
Volume of the large cube = 33+43+53 = 216 cu.cm.
Let the edge of the large cube be a.
So, a3= 216
=>a = 6 cm.
Required ratio = 632+42+52662=2518
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