# Time and Distance Questions

**FACTS AND FORMULAE FOR TIME AND DISTANCE QUESTIONS**

**1.**

**2. **x km/hr =

**3. **x m/sec =

**4.** If the ratio of the speeds of A and B is a:b , then the ratio of the times taken by them to cover the same distance is or b : a

**5. **Suppose a man covers a certain distance at x km/ hr and an equal distance at y km/hr . Then, the average speed during the whole journey iskm/hr.

A) 456 kms | B) 482 kms |

C) 552 kms | D) 556 kms |

Explanation:

Total distance travelled in 12 hours =(35+37+39+.....upto 12 terms)

This is an A.P with first term, a=35, number of terms,

n= 12,d=2.

Required distance = 12/2[2 x 35+{12-1) x 2]

=6(70+23)

= 552 kms.

A) 100 m | B) 150 m |

C) 190 m | D) 200 m |

Explanation:

Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr

Distance covered in 6 minutes = km = km = 100 m

Distance between the thief and policeman = (200 – 100) m = 100 m.

A) 600 | B) 750 |

C) 1000 | D) 1250 |

Explanation:

speed = (5x5/18)m/sec

= 25/18 m/sec.

Distance covered in 15 minutes = (25/18 x 15 x 60)m

= 1250 m.

A) 30 km/h | B) 15 km/h |

C) 25 km/h | D) 20 km/h |

Explanation:

If the speed of the faster horse be and that of slower horse be then

and

Now, you can go through options.

The speed of slower horse is 20km/h

Since, 20+30=50

and

A) 720 | B) 180 |

C) 75 | D) 65 |

Explanation:

The hour hand moves from pointing to 12 to pointing to half way between 2 and 3. The angle covered between each hour marking on the clock is 360/12 = 30. Since the hand has covered 2.5 of these divisions the angle moved through is 75.