# Alligation or Mixture Questions

A) 10 | B) 20 |

C) 21 | D) 25 |

Explanation:

Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively

Quantity of A in mixture left = litres.

Quantity of B in mixture left = litres.

So, the can contained 21 litres of A.

A) 18 litres | B) 24 litres |

C) 32 litres | D) 42 litres |

Explanation:

Let the quantity of the wine in the cask originally be x litres

Then, quantity of wine left in cask after 4 operations =litres

A) 1/3 | B) 1/4 |

C) 1/5 | D) 1/7 |

Explanation:

Suppose the vessel initially contains 8 litres of liquid.

Let x litres of this liquid be replaced with water.

Quantity of water in new mixture = litres.

Quantity of syrup in new mixture = litres.

=> 5x + 24 = 40 - 5x

=> 10x = 16 => x = 8/5

So, part of the mixture replaced = = 1/5.

A) 400 kg | B) 560 kg |

C) 600 kg | D) 640 kg |

Explanation:

By the rule of alligation:

Profit of first part Profit of second part

So, ratio of 1st and 2nd parts = 4 : 6 = 2 : 3.

Quantity of 2nd kind = (3/5 x 1000)kg = 600 kg.

A) 26.34 litres | B) 27.36 litres |

C) 28 litres | D) 29.16 litres |

Explanation:

Amount of milk left after 3 operations

litres