# Area Question & Answers

## Area

Quantitative aptitude questions are asked in many competitive exams and placement exam. Area is a category in Quantitative Aptitude. Quantitative aptitude questions given here are extremely useful for all kind of competitive exams like Common Aptitude Test (CAT), MAT, GMAT, IBPS Exam, CSAT, CLAT, Bank Competitive Exams, ICET, UPSC Competitive Exams, CLAT, SSC Competitive Exams, SNAP Test, KPSC, XAT, GRE, Defense Competitive Exams, L.I.C/ G. I.C Competitive Exams, Railway Competitive Exam, TNPSC, University Grants Commission (UGC), Career Aptitude Test (IT Companies) and etc., Government Exams etc.

We have a large database of “Area” Problems answered with explanation. These will help students who are preparing for all types of competitive examinations

A room is half as long again as it is broad. The cost of carpeting the at Rs. 5 per sq.m is Rs. 270 and the cost of papering the four walls at Rs. 10 per m2 is Rs. 1720. If a door and 2 windows occupy 8 sq. m, find the dimensions of the room.

 A) b=6;l=18;H=6 B) b=5;l=6;H=18 C) l=6;b=18;H=15 D) l=5;b=18;H=18

Explanation:

Let breadth = x metres, length = 3x metres, height = H metres.

Area of the floor=(Total cost of carpeting)/(Rate) = (270/5)$\inline m^{2}$= 54$\inline m^{2}$

$\inline x\times \frac{3x}{2}=54\; \; \Rightarrow x^{2}=\frac{54\times 2}\; \; \Rightarrow x=6$

So, breadth = 6 m and length =$\inline \frac{3(6)}{2}$ = 9 m.

Now, papered area = (1720/10) $\inline m^{2}$=  172$\inline m^{2}$

Area of 1 door and 2 windows = 8$\inline m^{2}$

Total area of 4 walls = (172 + 8) $\inline m^{2}$ = 180 $\inline m^{2}$

$\inline 2\times (9+6)H=180\; \; \Rightarrow H=6m$

Subject: Area - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

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A room 5m 55cm long and 3m 74cm broad is to be paved with square tiles.Find the least number of square tiles required to cover the floor?

 A) 156 B) 166 C) 176 D) 186

Explanation:

Area of the room=(544 * 374)

size of largest square tile= H.C.F of 544 & 374 = 34 cm

Area of 1 tile = (34  x  34) $\inline cm^{2}$

Number of tiles required== [(544 x 374) / (34 x 34)] = 176

Subject: Area - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

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A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?

 A) 315 B) 385 C) 415 D) 485

Explanation:

Let the areas of the two parts be x and (700-x) hectares

therefore, $\inline [x-(700-x)]=\frac{1}{5}[\frac{[x+(700-x)]}{2}]$

$\inline \Rightarrow 2x-700=70$

$\inline \Rightarrow x=385$

So, the two parts are 385 and 315.

Hence, Area of the smaller = 315 hectares

Subject: Area - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

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The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m

 A) 53800 B) 43800 C) 83800 D) 73800

Explanation:

perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126*126) - (120*120) = 246*6 sq m
cost of pavement = 246*6*50 = Rs. 73800

Subject: Area - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

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The length of a rectangular hall is 5m more than its breadth. The area of the hall is 750 m. The length of the hall is

 A) 20 B) 25 C) 30 D) 35

Explanation:

Le breadth= x meters

Then, length= (x+5)meters

x(x+5) = 750

x² + 5x - 750= 0

(x+30)(x-25)= 0

x = 25