# Area Question & Answers

## Area

Quantitative aptitude questions are asked in many competitive exams and placement exam. Area is a category in Quantitative Aptitude. Quantitative aptitude questions given here are extremely useful for all kind of competitive exams like Common Aptitude Test (CAT), MAT, GMAT, IBPS Exam, CSAT, CLAT, Bank Competitive Exams, ICET, UPSC Competitive Exams, CLAT, SSC Competitive Exams, SNAP Test, KPSC, XAT, GRE, Defense Competitive Exams, L.I.C/ G. I.C Competitive Exams, Railway Competitive Exam, TNPSC, University Grants Commission (UGC), Career Aptitude Test (IT Companies) and etc., Government Exams etc.

We have a large database of “Area” Problems answered with explanation. These will help students who are preparing for all types of competitive examinations

One side of a rectangular field is 15m and one of its diagonal is 17m. Find the area of field?

A) 110 | B) 120 |

C) 130 | D) 140 |

Explanation:

Other side = [(17*17) - (15*15)] = (289-225) = 8m

Area = 15 * 8 =120 sq. m

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Subject: Area - Quantitative Aptitude - Arithmetic AbilityExam Prep: Bank Exams

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The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

A) 2520 | B) 2420 |

C) 2320 | D) 2620 |

Explanation:

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.

Solving the two equations, we get: l = 63 and b = 40.

Area = (l x b) = (63 x 40) = 2520 m^2.

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Subject: Area - Quantitative Aptitude - Arithmetic AbilityExam Prep: Bank Exams

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A room of 5m 44cm long and 3m 74cm broad is to be paved with squre tiles. Find the least number of squre tiles required to cover the floor.

A) 136 | B) 146 |

C) 166 | D) 176 |

Explanation:

area of the room = 544 * 374 sq cm

size of largest square tile = H.C.F of 544cm and 374cm= 34cm

area of 1 tile = 34*34 sq cm

no. of tiles required = (544*374) / (34 * 34) = 176

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If a square and a rhombus stand on the same base, then the ratio of the areas of the square and the rhombus is:

A) 1:1 | B) 1:2 |

C) 1:3 | D) 1:4 |

Explanation:

A square and a rhombus on the same base are equal in area

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A rectangular parking space is marked out by painting three of its sides.If the length of the unpainted side is 9 feet, and the sum of the lengths of the painted sides is 37 feet, then what is the area of the parking space in square feet?

A) 126sq.ft | B) 120sq.ft |

C) 130sq.ft | D) 135sq.ft |

Explanation:

Let l = 9 ft.

Then l + 2b = 37

=> 2b = 37 – l = 37 – 9 = 28

b = 28/2 = 14 ft.

Area = lb = 9 × 14 = 126 sq. ft.

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Subject: Area - Quantitative Aptitude - Arithmetic AbilityExam Prep: Bank Exams

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