# Calendar Questions

Q:

What was the day on 15th august 1947 ?

 A) Friday B) Saturday C) Sunday D) Thursday

Explanation:

15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)

Odd days in 1600 years = 0

Odd days in 300 years = 1

46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day

Jan.   Feb.   Mar.   Apr.   May.   Jun.   Jul.   Aug

( 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 ) = 227 days = (32 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days.

Hence, as the number of odd days = 5 , given day is Friday.

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Q:

Today is Monday. After 61 days, it will be :

 A) Tuesday B) Monday C) Sunday D) Saturday

Explanation:

Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday.

$\inline \therefore$After 61 days, it will be Saturday.

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Q:

The last day of a century cannot be

 A) Monday B) Wednesday C) Tuesday D) Friday

Explanation:

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Q:

What was the day of the week on, 16th July, 1776?

 A) Tuesday B) Wednesday C) Monday D) Saturday

Explanation:

16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776)

Counting of odd days :

• 1600 years have 0 odd day.
• 100 years have 5 odd days.
• 75 years = (18 leap years + 57 ordinary years) =  [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days.

1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day.

Jan   Feb   Mar   Apr   May   Jun   Jul

31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 2 days)

$\inline \therefore$ Total number of odd days = (0 + 2) = 2.

Required day was 'Tuesday'.

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Q:

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

 A) Monday B) Friday C) Sunday D) Tuesday

Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days.

$\therefore$On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday