Calender

Quantitative aptitude questions are asked in many competitive exams and placement exam. Calendar is a category in Quantitative Aptitude. Quantitative aptitude questions given here are extremely useful for all kind of competitive exams like Common Aptitude Test (CAT), MAT, GMAT, IBPS Exam, CSAT, CLAT, Bank Competitive Exams, ICET, UPSC Competitive Exams, CLAT, SSC Competitive Exams, SNAP Test, KPSC, XAT, GRE, Defense Competitive Exams, L.I.C/ G. I.C Competitive Exams, Railway Competitive Exam, TNPSC, University Grants Commission (UGC), Career Aptitude Test (IT Companies) and etc., Government Exams etc.

We have a large database of "Calendar" Problems answered with explanation. These will help students who are preparing for all types of competitive examinations.

What was the day on 15th august 1947 ?

 A) Friday B) Saturday C) Sunday D) Thursday

Explanation:

15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)

Odd days in 1600 years = 0

Odd days in 300 years = 1

46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day

Jan. Feb. Mar. Apr. May. Jun. Jul. Aug

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 1 ) = 213 days = (30 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days.

Given day is Friday.

Subject: Calendar - Quantitative Aptitude - Arithmetic Ability

149

Today is Monday. After 61 days, it will be :

 A) Tuesday B) Monday C) Sunday D) Saturday

Explanation:

Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday.

$\inline \therefore$After 61 days, it will be Saturday.

Subject: Calendar - Quantitative Aptitude - Arithmetic Ability

228

The last day of a century cannot be

 A) Monday B) Wednesday C) Tuesday D) Friday

Explanation:

Subject: Calendar - Quantitative Aptitude - Arithmetic Ability

103

What was the day of the week on, 16th July, 1776?

 A) Tuesday B) Wednesday C) Monday D) Saturday

Explanation:

16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776)

Counting of odd days :

• 1600 years have 0 odd day.
• 100 years have 5 odd days.
• 75 years = (18 leap years + 57 ordinary years) =  [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days.

1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day.

Jan   Feb   Mar   Apr   May   Jun   Jul

31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 2 days)

$\inline \therefore$ Total number of odd days = (0 + 2) = 2.

Required day was 'Tuesday'.

Subject: Calendar - Quantitative Aptitude - Arithmetic Ability

49

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

 A) Monday B) Friday C) Sunday D) Tuesday

Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days.

$\therefore$On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday