# Compound Interest Questions

A) 10000 | B) 20000 |

C) 40000 | D) 50000 |

Explanation:

Let sum=Rs.x

C.I. when compounded half yearly =

C.I. when compounded annually =

=> x=20000

A) 4360 | B) 4460 |

C) 4560 | D) 4660 |

Explanation:

Let the sum be Rs.P.then

P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(ii)

On dividing,we get (1+R/100)^3=10025/6690=3/2.

Substituting this value in (i),we get:

P*(3/2)=6690 or P=(6690*2/3)=4460

Hence,the sum is rs.4460.

A) I only | B) II and III only |

C) All I, II and III | D) I only or II and III only |

Explanation:

Thus I only or (II and III) give answer.

Correct answer is (D)

A) 5430 | B) 4430 |

C) 3430 | D) 2430 |

Explanation:

Let each installment be Rs.x. Then,

(P.W. of Rs.x due 1 year hence) + (P.W of Rs.x due 2 years hence) + (P.W of Rs. X due 3 years hence) = 7620.

Amount of each installment = Rs.3430

A) Rs.600 | B) Rs,6400 |

C) Rs.6500 | D) Rs.6600 |

Explanation:

The population grew from 3600 to 4800 in 3 years. That is a growth of 1200 on 3600 during three year span.

Therefore, the rate of growth for three years has been constant.

The rate of growth during the next three years will also be the same.

Therefore, the population will grow from 4800 by = 1600

Hence, the population three years from now will be 4800 + 1600 = 6400