# Numbers Questions

A) 21 | B) 11 |

C) 17 | D) 31 |

Explanation:

Let y be the total number of loaves

a be the remaining loaves after 1st thief

b be the remaining loaves after 2nd thief

and c, d..so on after 3 and 4 th

e = 0 be the remaining loaves after 5th thief

a = y - (y/2 + 1/2)

= y/2 - 1/2

b = a - (a/2 + 1/2)

= a/2 - 1/2

c = b - (b/2 + 1/2)

= b/2 - 1/2

d = c - (c/2 + 1/2)

= c/2 - 1/2

e = d - (d/2 + 1/2)

= d/2 - 1/2

we know that, e = 0,

thus by substitution, we get

d = 1

c = 3

b = 7

a = 15

y = 31

Therefore total number of bread loaves in bakery was 31.

A) 121 | B) 943 |

C) 462 | D) None |

Explanation:

Assume that the number is taken as XYZ.

Condition 1 => Z = sq.root(x) => Possible digits of X is 1,4,9

Condition 2 => Y = X + Z

X Y Z

1 2 1

4 6 2

9 12 3 => (wrong because it is 4 digit.)

and 121 is not divisible by 2

The answer is 462.

A) 19 | B) 23 |

C) 17 | D) 15 |

Explanation:

If he wants to give these books equally to 2 of his friends, then 1 book will remain, it means possible number of books = 15,17,19,21,23,25,27,29

If he wants to give these books equally to 3 of his friends, then 2 books will remain, it means possible number of books = 17,20,23,26,29

If he wants to give these books equally to 4 of his friends, then 3 book will remain, it means possible number of books = 15,19,23,27

common number is only 23 so it will be answer

A) 0 | B) 1 |

C) 3 | D) 5 |

Explanation:

All powers of 6 has 6 in units place so answer will definitely be 1.

A) Rs. 13 and Rs. 17 | B) Rs. 17 and Rs. 19 |

C) Rs. 23 and Rs. 17 | D) Rs. 13 and Rs. 19 |

Explanation:

If fares for cities L and M from K are x and y respectively, then

2x + 3y = 77 or 6x + 9y = 231...(1)

3x + 2y = 73 or 6x + 4y = 146...(2)

subtracting 2 from 1, we get

5y = 85

y = Rs. 17 => x = Rs. 13