# Pipes and Cistern Questions

FACTS  AND  FORMULAE  FOR  PIPES  AND  CISTERN  QUESTIONS

1. Inlet : A pipe connected with a tank or a cistern or a reservoir, that fills it, is known as an inlet.

2. Outlet : A pipe connected with a tank or cistern or reservoir, emptying it, is known as an outlet.

(i) If a pipe can fill a tank in x hours, then:

part filled in 1 hour = 1/x

(ii) If a pipe can empty a tank in y hours, then:

part emptied in 1 hour = 1/y

(iii) If a pipe can fill a tank in x hours and another pipe can empty the full tank in y hours (where y > x), then on opening both the pipes, then the net part filled in 1 hour = $\left(\frac{1}{x}-\frac{1}{y}\right)$

(iv) If a pipe can fill a tank in x hours and another pipe can empty the full tank in y hours (where x > y), then on opening both the pipes,  the net part emptied in 1 hour = $\left(\frac{1}{y}-\frac{1}{x}\right)$

Q:

Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank?

 A) 10 min. 20 sec. B) 11 min. 45 sec. C) 12 min. 30 sec. D) 14 min. 40 sec.

Answer & Explanation Answer: D) 14 min. 40 sec.

Explanation:

Part filled in 4 minutes =4(1/15+1/20) = 7/15

Remaining part =(1-7/15) = 8/15

Part filled by B in 1 minute =1/20 : 8/15 :: 1:x

x = (8/15*1*20) =

The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec

43 28291
Q:

Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:

 A) 10 B) 12 C) 14 D) 16

Explanation:

Part filled in 2 hours = 2/6=1/3

Remaining part =$\left(1-\frac{1}{3}\right)=\frac{2}{3}$

(A + B)'s 7 hour's work = 2/3

(A + B)'s 1 hour's work = 2/21

C's 1 hour's work = { (A + B + C)'s 1 hour's work } - { (A + B)'s 1 hour's work }

=1/6-2/21 = 1/14

C alone can fill the tank in 14 hours.

24 12230
Q:

A pump can fill a tank with water in 2 hours. Because of a leak, it took $2\frac{1}{3}$ hours to fill the tank. The leak can drain all the water of the tank in:

 A) 7 hours B) 8 hours C) 12 hours D) 14 hours

Answer & Explanation Answer: D) 14 hours

Explanation:

If the total area of pump=1 part

The pumop take 2 hrs to fill 1 part

The pumop take1 hour to fill 1/2 portion

Due to lickage

The pumop take 7/3 hrs to fill 1 part

The pumop take1 hour to fill 3/7 portion

Now the difference of area = (1/2-3/7)=1/14

This 1/14 part of water drains in 1 hour

Total area=1 part of water drains in (1x14/1)hours= 14 hours

So the leak can drain all the water of the tank in 14 hours.

Leak will empty the tank in 14 hrs

22 10799
Q:

Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is:

 A) 60 gallons B) 100 gallons C) 120 gallons D) 180 gallons

Answer & Explanation Answer: C) 120 gallons

Explanation:

Work done by the waste pipe in 1 minute = [-ve sign means emptying]

Volume of $\frac{1}{40}$part = 3 gallons

Volume of whole = (3 x 40) gallons = 120 gallons.

11 8531
Q:

A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?

 A) 3 hrs 15 min B) 3 hrs 45 min C) 4 hrs 15 min D) 4 hrs 1

Answer & Explanation Answer: B) 3 hrs 45 min

Explanation:

Time taken by one tap to fill half of the tank = 3 hrs.

Part filled by the four taps in 1 hour =4*1/6 =2/3

Remaining part =$\left(1-\frac{1}{2}\right)=\frac{1}{2}$

$\frac{2}{3}:\frac{1}{2}::1:x$

=> x = $\left(\frac{1}{2}*1*\frac{3}{2}\right)=\frac{3}{4}$

So, total time taken = 3 hrs. 45 mins.

12 7861
Q:

A booster pump can be used for filling as well as for emptying a tank. The capacity of the tank is 2400  ${m}^{3}\phantom{\rule{0ex}{0ex}}$. The emptying capacity of the tank is 10 ${m}^{3}$ per minute higher than its filling capacity and the pump needs 8 minutes lesser to empty the tank than it needs to fill it. What is the filling capacity of the pump?

 A) 50 m^3/min B) 60 m^3/min C) 72 m^3/min D) None of these

Answer & Explanation Answer: A) 50 m^3/min

Explanation:

Let the filling capacity of the pump be x ${m}^{3}$/min.

Then, emptying capacity of the pump=(x+10)${m}^{3}$/min.

so,

17 7477
Q:

Three taps A,B and C can fill a tank in 12,15 and 20 hours respectively. If A is open all the time and B ,C are open for one hour each alternatively, the tank will be full in:

 A) 6 hrs B) 20/3 hrs C) 7 hrs D) 15/2 hrs

Answer & Explanation Answer: C) 7 hrs

Explanation:

Now, it is  the turn of A and B (3/20) part is filled by A and B in 1 hour.

Therefore, Total  time taken to fill the tank =(6+1)hrs= 7 hrs

16 7199
Q:

A water tank is two-fifth full.Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes.If both the pipes are open,how long will it take to empty or fill the tank completely?

 A) 6 min.to empty B) 6 min.to fill C) 9 min.to empty D) 9 min.to fill

Answer & Explanation Answer: A) 6 min.to empty

Explanation:

Clearly,pipe B is faster than pipe A and so,the tank will be emptied.

part to be emptied = 2/5

part emptied by (A+B) in 1 minute=$\left(\frac{1}{6}-\frac{1}{10}\right)=\frac{1}{15}$

$\frac{1}{15}:\frac{2}{5}::1:x$

$\frac{2}{5}*15=6mins$

so, the tank will be emptied in 6 min