# Problems on Numbers Questions

A) 35 | B) 36 |

C) 37 | D) 39 |

Explanation:

Let the ten's digit be x. Then, unit's digit = 2x + 1.

[10x + (2x + 1)] - [{10 (2x + 1) + x} - {10x + (2x + 1)}] = 1

<=> (12x + 1) - (9x + 9) = 1 <=> 3x = 9, x = 3.

So, ten's digit = 3 and unit's digit = 7. Hence, original number = 37.

A) 12 | B) 24 |

C) 36 | D) 48 |

Explanation:

Let the ten's digit be x.

Then, unit's digit = x + 2.

Number = 10x + (x + 2) = 11x + 2

Sum of digits = x + (x + 2) = 2x + 2.

(11x + 2) (2x + 2) = 144

=>

=> (x - 2)(11x + 35) = 0

=> x = 2

Hence, Required Number = 11x + 2 = 24

A) 30 | B) 40 |

C) 50 | D) 60 |

Explanation:

Let the numbers be 4x, 5x and 6x, Then, (4x + 5x + 6x ) / 3 = 25

=> 5x = 25

=> x = 5.

Largest number 6x = 30.

A) 100 | B) 200 |

C) 300 | D) 400 |

Explanation:

Let the numbers be x and y.

Then, xy = 9375 and x/y = 15.

=>

=> y = 25

=> x = 15y = 15 x 25 = 375.

Sum of the numbers = 375 + 25 = 400.

A) 7/11 | B) 8/11 |

C) 9/11 | D) 10/11 |

Explanation:

Let the numerator be x Then, denominator = x + 3.

Now. (x + 4)/(x + 3) +4 = 4/5 <=> 5 (x + 4) = 4(x + 7)

=> x = 8.

The fraction is 8/11.