Time and Work Questions


P can complete a work in 12 days working 8 hours a day.Q can complete the same work in 8 days working 10 hours a day. If both p and Q work together,working 8 hours a day,in how many days can they complete the work?

A) 60/11 B) 61/11
C) 71/11 D) 72/11
Answer & Explanation Answer: A) 60/11


P can complete the work in (12 * 8) hrs = 96 hrs

Q can complete the work in (8 * 10) hrs=80 hrs

\inline {\color{Black}\therefore } P's 1 hour work=1/96   and Q's 1 hour work= 1/80

(P+Q)'s 1 hour's work =\inline {\color{Black} \left ( \frac{1}{96}+\frac{1}{80} \right )} =\inline {\color{Black} \frac{11}{480}}

so both P and Q will finish the work in \inline {\color{Black} \frac{480}{11}} hrs

\inline {\color{Black} \therefore } Number of days of 8 hours each = \inline {\color{Black} \left ( \frac{480}{11} \times \frac{1}{8}\right )=\frac{60}{11}}

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7 2502

A group of workers was put on a job. From the second day onwards, one worker was withdrawn each day. The job was finished when the last worker was withdrawn. Had no worker been withdrawn at any stage, the group would have finished the job in 55% of the time. How many workers were there in the group?

A) 50 B) 40
C) 45 D) 10
Answer & Explanation Answer: D) 10


It can be solved easily through option.

        \inline \left ( 10+9+8+....+1 \right )=10\left ( 10\times \frac{55}{100} \right )

                     55 = 55     Hence correct



        \inline \frac{n(n+1)}{2}=n\times \frac{55n}{100}

         => n= 10

In Both cases total work is 55man-days.

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8 2289

A can do a piece of work in 18 days, B in 27 days, C in 36 days. They start worked together . But only C work till the completion of work. A leaves 4 days and B leaves 6 days before the completion of work. In how many days work be completed?


Let the work be completed in x days

(x-4)days of A + (x-6)days of B + x days of C = 1

\inline \Rightarrow \inline \frac{x-4}{18}+\frac{x-6}{27}+\frac{x}{36}=1

\inline \Rightarrow \frac{13x-48}{108}=1

           x = 12

\inline \therefore Total time = 12 days


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4 2084

A Contractor employed a certain number of workers  to finish constructing a road in a certain scheduled time. Sometime later, when a part of work had been completed, he realised that the work would get delayed by three-fourth of the  scheduled time, so he at once doubled the no of workers and thus he managed to finish the road on the scheduled time. How much work he had been completed, before increasing the number of workers?

A) 10 % B) 14 2/7 %
C) 20 % D) Can't be determined
Answer & Explanation Answer: B) 14 2/7 %


Let he initially employed x workers which works for D days and he estimated 100 days for the whole work and then he doubled the worker for (100-D) days.

      D * x +(100- D) * 2x= 175x

       =>  D= 25 days

Now , the work done in 25 days = 25x

               Total work = 175x

therefore, workdone before increasing the no of workers = \frac{25x}{175x}\times 100=14\frac{2}{7} %

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14 2068

A is thrice efficient as B and C is twice as efficient as B. what is the ratio of number of days taken by A,B and C, when they work individually?

A) 2:6:3 B) 2:3:6
C) 1:2:3 D) 3:1:2
Answer & Explanation Answer: A) 2:6:3


                                                       A    :    B    :    C

Ratio of efficiency                    3     :    1    :    2

Ratio of No.of days               \inline \fn_jvn \left \{ \inline \fn_jvn \frac{1}{3}     :    \inline \fn_jvn \frac{1}{1}    :   \inline \fn_jvn \frac{1}{2}  \inline \fn_jvn \left \right \}

     or                                              2    :    6    :    3

Hence A is correct.     \inline \fn_jvn \left [ \because Time \prec \frac{1}{Eficiency} \right ]

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9 1929