0

# If the price of 23 toys is 276, then what will the price of 12 toys ?

 A) 144 B) 148 C) 156 D) 186

Explanation:

Less toys, Less Price (Direct Proportion)
So, let the price be Rs. x
then,

23:12::276:x    => x=(276*12)/23

=> x=144

So price of 12 toys will be Rs. 144

Tags:

• Related Questions

If 36 men can do a piece of work in 25 hours, in how mwny hours will15 men do it?

 A) 40 B) 50 C) 60 D) 70

Explanation:

Let the required no of hours be x. Then

Less men , More hours    (Indirct Proportion)

$\inline&space;\fn_jvn&space;\therefore$  15:36 ::25:x  $\inline&space;\fn_jvn&space;\Leftrightarrow$ (15 x X)=(36 x 25)  $\inline&space;\fn_jvn&space;\Leftrightarrow$ $\inline&space;\fn_jvn&space;x=\frac{36\times&space;25}{15}=60$

Hence, 15 men can do it in 60 hours.

Subject: Chain Rule - Quantitative Aptitude - Arithmetic Ability

19

If 20 men can build a wall 56 meters long in 6 days , what length of  a similar wall can be  built by 35 men in 3 days?

 A) 46 B) 47 C) 48 D) 49

Explanation:

Let the required length be x meters

More men, More length built     (Direct proportion)

Less days, Less length built      (Direct Proportion)

$\inline&space;\fn_jvn&space;\left.\begin{matrix}&space;Men\:&space;\:&space;\:&space;20:35\\&space;Days\:&space;6:3&space;\end{matrix}\right\}::56:x$

$\inline&space;\fn_jvn&space;\therefore$  (20 x 6 x X)=(35 x 3 x 56) $\inline&space;\fn_jvn&space;\Leftrightarrow$  $\inline&space;\fn_jvn&space;x=\frac{35\times&space;3\times&space;56}{120}&space;=49$

Hence, the required length is 49 m.

Subject: Chain Rule - Quantitative Aptitude - Arithmetic Ability

21

2 men and 7 boys can do a piece of work in 14 days; 3 men and 8 boys can do the same in 11 days. Then, 8 men and 6 boys can do three times the amount of this work in

 A) 18 days B) 21 days C) 24 days D) 30 days

Explanation:

$\inline&space;\fn_jvn&space;(2\times&space;14)&space;men&space;+(7\times&space;14)boys=(3\times&space;11)men+(8\times&space;11)boys$

$\inline&space;\fn_jvn&space;\Leftrightarrow$  5 men= 10 boys  $\inline&space;\fn_jvn&space;\Leftrightarrow$  1man= 2 boys

$\inline&space;\fn_jvn&space;\therefore$  (2 men+ 7 boys) = (2 x 2 +7) boys = 11 boys

( 8 men + 6 boys) = (8 x 2 +6) boys = 22 boys.

Let the required  number of days be x.

More boys , Less days     (Indirect proportion)

More work , More days    (Direct proportion)

$\inline&space;\fn_jvn&space;\left.\begin{matrix}&space;Boys\:&space;22:11\\&space;Work\:&space;1:3&space;\end{matrix}\right\}::14:x$

$\inline&space;\fn_jvn&space;\therefore&space;\:&space;\:&space;(22\times&space;1\times&space;x)=(11\times&space;3\times&space;14)$   $\inline&space;\fn_jvn&space;\Leftrightarrow$  $\inline&space;\fn_jvn&space;x=&space;\frac{462}{22}=21$

Hence, the required number of days = 21

Subject: Chain Rule - Quantitative Aptitude - Arithmetic Ability

7

A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the begining and 100 more  after 35 days and completes the work in stipulated time. If he had not  engaged  the additional men, how many days  behind schedule would it be finished?

 A) 3 B) 5 C) 6 D) 9

Explanation:

$\inline&space;\fn_jvn&space;[(100\times&space;35)+(200\times&space;5)]$ men can finish the work in 1 day

$\inline&space;\fn_jvn&space;\therefore$  4500 men can finish the work in 1 day. 100 men can finish it in $\inline&space;\fn_jvn&space;\frac{4500}{100}$  = 45 days.

This is 5 days behind Schedule

Subject: Chain Rule - Quantitative Aptitude - Arithmetic Ability

4

A certain number of men can finish a piece of work in 100 days. If there were 10 men less, it would take 10 days more for the work to be finished. How many men were there originally?

 A) 75 B) 82 C) 100 D) 110

Explanation:

Originally let there be x men.

Less men, More days     (Indirect Proportion)

$\inline&space;\fn_jvn&space;\therefore$  (x-10) : x  :: 100 :110   $\inline&space;\fn_jvn&space;\Leftrightarrow$  $\inline&space;\fn_jvn&space;(x-10)\times&space;110=x\times&space;100$  $\inline&space;\fn_jvn&space;\Leftrightarrow$  10x= 1100    $\inline&space;\fn_jvn&space;\Leftrightarrow$  x= 110