21
Q:

Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?

A) 3.6 B) 6
C) 18 D) Cannot be determined

Answer:   B) 6



Explanation:

Explanation:

 

Let rate = R% and time = R years.

 

Then, 1200*R*R100=432

 

12R2=432

 

=>R2=36R=6

Q:

What is the interest rate per annum, if a sum of money invested at compound interest amount to Rs. 2400 in 3 years and in 4 years to Rs. 2,520?

A) 3.5% B) 4%
C) 5% D) 6.5%
 
Answer & Explanation Answer: C) 5%

Explanation:

Let 'R%' be the rate of interest

From the given data,

25202400 = 1 + R10041 + R10031 + R100 = 6360R = 5

 

Hence, the rate of interest R = 5% per annum.

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0 116
Q:

A sum of Rs. 8,000 is deposited for 3 years at 5% per annum compound interest (compounded annually). The difference of interest for 3 years and 2 years will be

 

A) Rs. 387 B) Rs. 441
C) Rs. 469 D) Rs. 503
 
Answer & Explanation Answer: B) Rs. 441

Explanation:

Given principal amount = Rs. 8000

Time = 3yrs

Rate = 5%

C.I for 3 yrs = 8000 x 105100 x 105100 x 105100 - 8000= Rs. 1261

 

Now, C.I for 2 yrs = 8000 x 105100 x 105100= Rs. 820 

 

Hence, the required difference in C.I is 1261 - 820 = Rs. 441

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0 165
Q:

Simple interest on a certain sum at 7% per annum for 4 years is Rs. 2415. What will be the compound interest on the same principal at 4% per annum in two years?

A) Rs. 704 B) Rs. 854
C) Rs. 893 D) Rs. 914
 
Answer & Explanation Answer: A) Rs. 704

Explanation:

We know that,

S.I. = PTR100 P = S.I x 100T x RAnd also,C.I = P1 + R100n- 1

From given data, P = Rs. 8625

Now, C.I  = 86251+41002-1= 862526252-1= 8625676625-1= 8625 x 51625C.I = Rs. 703.80

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3 438
Q:

Find the compound interest on Rs. 6,500 for 4 years if the rate of interest is 10% p.a. for the first 2 years and 20% per annum for the next 2 years? 

A) Rs. 3845 B) Rs. 4826
C) Rs. 5142 D) Rs. 4415
 
Answer & Explanation Answer: B) Rs. 4826

Explanation:

We know the formula for calculating

The compound interest C = P1 + r100n - 1 where P = amount, r = rate of interest, n = time

Here P = 5000, r1 = 10, r2 = 20

Then C = 65001 + 101002 x 1 + 201002 - 1= 6500 x 18562500= 65 x 185625

C = Rs. 4826.

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6 370
Q:

What is the difference between the compound interests on Rs. 5000 for 11⁄2 years at 4% per annum compounded yearly and half-yearly?

A) Rs. 1.80 B) Rs. 2.04
C) Rs. 3.18 D) Rs. 4.15
 
Answer & Explanation Answer: B) Rs. 2.04

Explanation:

Compound Interest for 1 12 years when interest is compounded yearly = Rs.(5304 - 5000)


Amount after 112 years when interest is compounded half-yearly 


Compound Interest for 1 12 years when interest is compounded half-yearly = Rs.(5306.04 - 5000)


Difference in the compound interests = (5306.04 - 5000) - (5304 - 5000)= 5306.04 - 5304 = Rs. 2.04

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4 428
Q:

The difference between simple interest and compound interest of a certain sum of money at 20% per annum for 2 years is Rs. 56. Then the sum is :

A) Rs. 3680 B) Rs. 2650
C) Rs. 1400 D) Rs. 1170
 
Answer & Explanation Answer: C) Rs. 1400

Explanation:

We know thatThe Difference between Compound Interest and Simple Interest for n years at R rate of interest is given by C.In - S.In = PR100n

Here n = 2 years, R = 20%, C.I - S.I = 56

56 = P201002=> P = 56 x 52=> P = 56 x 25=> P = Rs. 1400

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10 483
Q:

Find the compound interest on Rs. 2680 at 8% per annum for 2 years ?

A) Rs. 664.21 B) Rs. 548.68
C) Rs. 445.95 D) Rs. 692.57
 
Answer & Explanation Answer: C) Rs. 445.95

Explanation:

We know Compound Interest = C.I. = P1+r100t - 1

Here P = 2680, r = 8 and t = 2

C.I. = 26801 + 81002-1= 268027252-12= 26802725+12725-1= 2680 5225×225

= (2680 x 52 x 2)/625

= 445.95

 

Compound Interest = Rs. 445.95

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9 541
Q:

The compound interest on Rs. 8000 for 3 year at 10% p.a. is

A) 2648 B) 2145
C) 2587 D) 2784
 
Answer & Explanation Answer: A) 2648

Explanation:

8000 × 33.1% = 2648

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16 758