9
Q:

# Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?

 A) 3.6 B) 6 C) 18 D) Cannot be determined

Answer:   B) 6

Explanation:

Explanation:

Let rate = R% and time = R years.

Then, $\inline \fn_cm \left ( \frac{1200\times R\times R}{100} \right )=432$

$\inline \fn_cm \Rightarrow 12R^{2}=432$

$\inline \fn_cm \Rightarrow R^{2}=36\Rightarrow R=6$

Q:

The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned  ?

 A) Rs. 11828.80 B) Rs. 19828.80 C) Rs. 9828.80 D) Rs. 19328.80

Answer & Explanation Answer: B) Rs. 19828.80

Explanation:

Let the sum be Rs. P
P{ $\inline \fn_jvn \small \left [ 1+\frac{8}{100} \right ]^{2}$ - 1 } = 2828.80

It is in the form of  $\inline \fn_jvn \small a^{2}-b^{2}=(a+b)(a-b)$

P(8/100)(2 + 8/100) = 2828.80

P = 2828.80 / (0.08)(2.08)

= 1360/0.08 = 17000

Principal + Interest = Rs. 19828.80

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2 51
Q:

Find the C.I. on Rs. 15,225 for 9 months at 16% per annum compounded quarterly ?

 A) Rs. 1911 B) Rs. 1909 C) Rs. 1901 D) Rs. 1907

Answer & Explanation Answer: C) Rs. 1901

Explanation:

P = Rs. 15225, n = 9 months = 3 quarters, R = 16% p.a. per quarter.

Amount = $\inline \fn_jvn \small \left [ 15225x\left ( 1+\frac{4}{100} \right )^{3} \right ]$

= (15225 x 26/25 x 26/25 x 26/25) = Rs. 17126.05

=> C.I. = 17126 - 15625 = Rs. 1901.05.

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1 24
Q:

The least number of complete years in which a sum of money put out at 20% C.I. will be more than doubled is  ?

 A) 3 years B) 4 years C) 2.5 years D) 2 years

Answer & Explanation Answer: B) 4 years

Explanation:

$\inline \fn_jvn \small P(1 + 20/100)^{n}$ > 2P or $\inline \fn_jvn \small \left ( \frac{6}{5}\right )^{n}$ > 2

Now, (6/5 x 6/5 x 6/5 x 6/5) > 2.

So, n = 4 years.

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3 34
Q:

Albert invested Rs. 8000 in a scheme for 2 years at compound interest rate 5% p.a. How much amount will Albert get on maturity of the fixed deposit  ?

 A) Rs. 8840 B) Rs. 8800 C) Rs. 8810 D) None

Answer & Explanation Answer: D) None

Explanation:

Amount = $\inline \fn_jvn \small \left [ 8000x\left ( 1 + \frac{5}{100} \right )^{2} \right ]$

= 8000 x 21/20 x 21/20

= Rs. 8820

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1 77
Q:

Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest ?

 A) 20% p.a B) 15% p.a C) 18% p.a D) 24% p.a

Answer & Explanation Answer: A) 20% p.a

Explanation:

Rs.1440 - 1200 = Rs.240 is the interest on Rs.1200 for one year.

Rate of interest = (100 x 240) / (1200) = 20% p.a

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