# Bank Exams Questions

Q:

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

 A) 1 B) 2 C) 3 D) 4

Explanation:

Area of the park = (60 x 40) = 2400$\inline m^{2}$

Area of the lawn = 2109$\inline m^{2}$

Area of the crossroads = (2400 - 2109) = 291$\inline m^{2}$

Let the width of the road be x metres. Then,

$\inline 60x+40x-x^{2}=291$

$\inline x^{2}-100x+291=0$

(x - 97)(x - 3) = 0
x = 3.

7 7969
Q:

A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is

 A) 136 B) 236 C) 336 D) 436

Explanation:

let ABCD be the given parallelogram

area of parallelogram ABCD = 2 x (area of triangle ABC)

now a = 30m, b = 14m and c = 40m

$\inline \fn_jvn s=\frac{1}{2}\times \left ( 30+14+40 \right ) = 42$

Area of triangle ABC = $\inline&space;{\color{Black}\sqrt{s(s-a)(s-b)(s-c)}}$

= $\inline&space;{\color{Black}\sqrt{42(12)(28)(2)}}$= 168sq m

area of parallelogram ABCD = 2 x 168 = 336 sq m

16 7923
Q:

The diagonal of a rectangle is $\inline \sqrt{41}$ cm and its area is 20 sq. cm. The perimeter of the rectangle must be:

 A) 18 B) 28 C) 38 D) 48

Explanation:

$\inline \sqrt{l^{2}+b^{2}}=\sqrt{41}$ (or)   ${\color{Black}&space;l^{2}+b^{2}=41}$

Also, $\inline lb=20$

${\color{Black}&space;(l+b)^{2}=l^{2}+b^{2}+2lb}$

= 41 + 40 = 81

(l + b) = 9.

Perimeter = 2(l + b) = 18 cm.

103 7253
Q:

A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be

 A) 7744 B) 8844 C) 5544 D) 4444

Explanation:

length of wire = ${\color{Blue}2&space;\Pi&space;r}$= 2 *(22/7 )*56 = 352 cm
side of the square = 352/4 = 88cm
area of the square = 88*88 = 7744sq cm

19 7218
Q:

If log 2 = 0.30103, Find the number of digits in 256 is

 A) 17 B) 19 C) 23 D) 25

${\color{Black}\log&space;(2^{56})=(56\times0.30103)&space;}$ =16.85768.
Hence, the number of digits in ${\color{Black}2^{56}&space;}$ is 17.