Bank Exams Questions

Q:

How many cubes of 3cm edge can be cut out of a cube of 18cm edge

 A) 36 B) 232 C) 216 D) 484

Explanation:

number of cubes=(18 x 18 x 18) / (3 x 3 x 3) = 216

63 16210
Q:

The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is

 A) 49 B) 154 C) 378 D) 1078

Explanation:

The diameter is equal to the shortest side of the rectangle.

Therefore,

24 15792
Q:

The length of a rectangular hall is 5m more than its breadth. The area of the hall is 750 m. The length of the hall is

 A) 20 B) 25 C) 30 D) 35

Explanation:

Then, length = (x+5)m

x(x+5) = 750

x² + 5x - 750= 0

(x+30)(x-25)= 0

x = 25

34 15792
Q:

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

 A) 1 B) 2 C) 3 D) 4

Explanation:

Area of the park = (60 x 40) = 2400${m}^{2}$

Area of the lawn = 2109${m}^{2}$

Area of the crossroads = (2400 - 2109) = 291${m}^{2}$

Let the width of the road be x metres. Then,

$60x+40x-{X}^{2}=291$

${x}^{2}-100x+291=0$

(x - 97)(x - 3) = 0
x = 3.

17 15502
Q:

Microsoft Office is an example of a________

 A) Closed source software B) Open source software C) Horizontal market software D) vertical market software

Explanation:

Filed Under: Computer
Exam Prep: Bank Exams

79 15267
Q:

A sum of money amounts to Rs.6690 after 3 years and to Rs.10,035 after 6 years on compound interest.find the sum.

 A) 4360 B) 4460 C) 4560 D) 4660

Explanation:

Let the sum be Rs.P.then
P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(ii)
On dividing,we get (1+R/100)^3=10025/6690=3/2.
Substituting this value in (i),we get:
P*(3/2)=6690 or P=(6690*2/3)=4460
Hence,the sum is rs.4460.

45 15149
Q:

The difference between compound interest and simple interest on a sum for two years at 8% per annum, where the interest is compounded annually is Rs.16. if the interest were compounded half yearly , the difference in two interests would be nearly

 A) Rs.24.64 B) Rs.21.85 C) Rs.16 D) Rs.16.80

Explanation:

For 1st year S.I =C.I.

Thus, Rs.16 is the S.I. on S.I. for 1 year, which at 8% is thus Rs.200

i.e S.I on the principal for 1 year is Rs.200

Principle = $Rs.\frac{100*200}{8*1}$ = Rs.2500

Amount for 2 years, compounded half-yearly

$Rs.\left[2500*{\left(1+\frac{4}{100}\right)}^{4}\right]=Rs.2924.4$

C.I = Rs.424.64

Also, $S.I=Rs.\left(\frac{2500*8*2}{100}\right)=Rs.400$

Hence, [(C.I) - (S.I)] = Rs. (424.64 - 400) = Rs.24.64

24 15091
Q:

Find the ratio of the areas of the incircle and circumcircle of a square.

 A) 1:1 B) 1:2 C) 1:3 D) 1:4

Explanation:

Let the side of the square be x. Then, its diagonal = $\sqrt{2{x}^{2}}=\sqrt{2x}$

Radius of incircle = $\frac{x}{2}$

Radius of circum circle= $\sqrt{2}×\frac{x}{2}=\frac{x}{\sqrt{2}}$

Required ratio = $\frac{{\mathrm{\pi x}}^{2}}{4}:\frac{{\mathrm{\pi x}}^{2}}{2}=\frac{1}{4}:\frac{1}{2}=1:2$