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Bank Exams Questions

A) 4360 | B) 4460 |

C) 4560 | D) 4660 |

Explanation:

Let the sum be Rs.P.then

P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(ii)

On dividing,we get (1+R/100)^3=10025/6690=3/2.

Substituting this value in (i),we get:

P*(3/2)=6690 or P=(6690*2/3)=4460

Hence,the sum is rs.4460.

A) 1:1 | B) 1:2 |

C) 1:3 | D) 1:4 |

Explanation:

Let the side of the square be x. Then, its diagonal =

Radius of incircle =

Radius of circum circle=

Required ratio =

A) 2109 | B) 3109 |

C) 4109 | D) 6109 |

Explanation:

Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.

Amount = Rs'. [8000 X (1+(15/100))^2 X (1+((1/3)*15)/100)]

=Rs. [8000 * (23/20) * (23/20) * (21/20)]

= Rs. 11109. .

:. C.I. = Rs. (11109 - 8000) = Rs. 3109.

A) 1 | B) 2 |

C) 3 | D) 4 |

Explanation:

Area of the park = (60 x 40) = 2400

Area of the lawn = 2109

Area of the crossroads = (2400 - 2109) = 291

Let the width of the road be x metres. Then,

(x - 97)(x - 3) = 0

x = 3.

A) 20 | B) 25 |

C) 30 | D) 35 |

Explanation:

Let breadth = x m

Then, length = (x+5)m

x(x+5) = 750

x² + 5x - 750= 0

(x+30)(x-25)= 0

x = 25