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GATE Questions

A) 3.25% loss | B) 13.742% loss |

C) 3.25% gain | D) 13.742% gain |

Explanation:

Let CP = 100,

42 % increase => SP = 142

10 % discount in SP => ((142 x 10)/100) = 14.2

So 1st SP = (142 - 14.2) = 127.8, again 12 % discount in 1st SP ((127.8 x 11)/100) = 14.058

2nd SP = (127.8 - 14.058) = 113.742,

So finally CP = 100, SP = 113.742, => gain = 13.742%.

A) All frustrated people are drug addicts | B) Frustrated people are whimsical |

C) All drug addicts are artists | D) Some artists may be drug addicts |

A) Rs. 1800 | B) Rs. 2000 |

C) Rs. 1400 | D) Rs. 1250 |

Explanation:

2500 in 5th year and 3000 in 7th year

So in between 2 years Rs. 500 is increased => for a year 500/2 = 250

So, per year it is increasing Rs.250 then in 5 years => 250 x 5 = 1250

Hence, the initial amount must be 2500 - 1250 = Rs. 1250

A) 5:3 | B) 1:4 |

C) 4:1 | D) 9:1 |

Explanation:

Milk = 3/5 x 20 = 12 liters, water = 8 liters

If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.

Remaining milk = 12 - 6 = 6 liters

Remaining water = 8 - 4 = 4 liters

10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.

The ratio of milk and water in the new mixture = 16:4 = 4:1

If the process is repeated one more time and 10 liters of the mixture are removed,

then amount of milk removed = 4/5 x 10 = 8 liters.

Amount of water removed = 2 liters.

Remaining milk = (16 - 8) = 8 liters.

Remaining water = (4 -2) = 2 liters.

Now 10 lts milk is added => total milk = 18 lts

The required ratio of milk and water in the final mixture obtained

= (8 + 10):2 = 18:2 = 9:1.

A) 90 mts | B) 150 mts |

C) 120 mts | D) 100 mts |

Explanation:

We know that

distance= speed * time

d =

d= 100 mts.