Bank PO Questions and Answers with Explanation, Job Roles

Q:

If the radius of a circle is decreased by 50%, find the percentage decrease in its area.

A) 55%	B) 65%
C) 75%	D) 85%

Answer & Explanation Answer: C) 75%

Explanation:

Let original radius = R.

New radius = $\frac{50}{100}R$ = $\frac{R}{2}$

Original area = $\prod R^{2}$ and new area = $\prod(\frac{R}{2})^{2}=\frac{\prod R^{2}}{4}$

Decrease in area = $\frac{3\prod R^{2}}{4}\times \frac{1}{\prod R^{2}}\times 100$ = 75%

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Filed Under: Area - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

52 19615

Q:

If log 27 = 1.431, then the value of log 9 is

A) 0.754	B) 0.854
C) 0.954	D) 0.654

Answer & Explanation Answer: C) 0.954

Explanation:

log 27 = 1.431
${\color{Black} \Rightarrow \log (3^{3})=1.431}$
3 log 3 = 1.431
log 3 = 0.477
log 9 = ${\color{Black} \log (3^{2})}$ = 2 log 3 = (2 x 0.477) = 0.954

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Filed Under: Logarithms - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

30 19614

Q:

A sum of money lent at compound interest for 2 years at 20% per annum would fetch Rs.482 more, if the interest was payable half yearly than if it was payable annually . The sum is

A) 10000	B) 20000
C) 40000	D) 50000

Answer & Explanation Answer: B) 20000

Explanation:

Let sum=Rs.x

C.I. when compounded half yearly = $\left [ x(1+\frac{10}{100})^{4}-x \right ]=\frac{4641}{10000}x$

C.I. when compounded annually = $\left [ x(\frac{20}{100})^{2}-x \right ]=\frac{11}{25}x$

$\therefore \frac{4641}{10000}x-\frac{11}{25}x=482$

=> x=20000

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Filed Under: Compound Interest - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

69 16664

Q:

A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

A) 30	B) 40
C) 50	D) 60

Answer & Explanation Answer: A) 30

Explanation:

Let the side of the square(ABCD) be x meters.

Then, AB + BC = 2x metres.

AC = $\sqrt{2}x$ = (1.41x) m.

Saving on 2x metres = (0.59x) m.

Saving % = $\frac{0.59x}{2x}\times 100$ = 30% (approx)

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Filed Under: Area - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

30 15875

Q:

A clock is set right at 5 a.m. The clock loses 16 minutes in 24 hours.What will be the true time when the clock indicates 10 p.m. on 4th day?

A) 11pm	B) 12pm
C) 1pm	D) 2pm

Answer & Explanation Answer: A) 11pm

Explanation:

Time from 5 am. on a day to 10 pm. on 4th day = 89 hours.

Now 23 hrs 44 min. of this clock = 24 hours of correct clock.

356/15 hrs of this clock = 24 hours of correct clock

89 hrs of this clock = (24 x 31556 x 89) hrs of correct clock.

= 90 hrs of correct clock.

So, the correct time is 11 p.m.

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Filed Under: Clocks - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

46 15357

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