Bank PO Questions and Answers with Explanation, Job Roles

Q:

A watch which gains uniformly ,is 5 min,slow at 8 o'clock in the morning on sunday and it is 5 min 48 sec.fast at 8 p.m on following sunday. when was it correct?

A) 7pm on wednesday	B) 20 min past 7pm on wednesday
C) 15min past 7pm on wednesday	D) 8pm on wednesday

Answer & Explanation Answer: B) 20 min past 7pm on wednesday

Explanation:

This sunday morning at 8:00 AM, the watch is 5 min. Slow, and the next sunday at 8:00PM it becomes 5 min 48 sec fast. The watch gains $5+5\tfrac{48}{60}$ min in a time of (7×24)+12 = 180 hours.

To show the correct time, it has to gain 5 min.

$\frac{54}{5}min\rightarrow 180 \; hours$

$5\; min\rightarrow ?$

$\Rightarrow \frac{5}{\frac{54}{5}}\times 180$

$83\frac{1}{3}hrs =72hrs+11\frac{1}{3}hrs=3days+11hrs+20min$

So the correct time will be shown on wednesday at 7:20 PM

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Filed Under: Clocks - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

28 10680

Q:

How many cubes of 3cm edge can be cut out of a cube of 18cm edge

A) 36	B) 232
C) 216	D) 484

Answer & Explanation Answer: C) 216

Explanation:

number of cubes=(18 x 18 x 18) / (3 x 3 x 3) = 216

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Filed Under: Volume and Surface Areas - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

47 10158

Q:

A sum of money amounts to Rs.6690 after 3 years and to Rs.10,035 after 6 years on compound interest.find the sum.

A) 4360	B) 4460
C) 4560	D) 4660

Answer & Explanation Answer: B) 4460

Explanation:

Let the sum be Rs.P.then
P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(ii)
On dividing,we get (1+R/100)^3=10025/6690=3/2.
Substituting this value in (i),we get:
P*(3/2)=6690 or P=(6690*2/3)=4460
Hence,the sum is rs.4460.

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Filed Under: Compound Interest - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

28 9482

Q:

A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is

A) 136	B) 236
C) 336	D) 436

Answer & Explanation Answer: C) 336

Explanation:

let ABCD be the given parallelogram

area of parallelogram ABCD = 2 x (area of triangle ABC)

now a = 30m, b = 14m and c = 40m

$s=\frac{1}{2}\times \left ( 30+14+40 \right ) = 42$

Area of triangle ABC = $\inline {\color{Black}\sqrt{s(s-a)(s-b)(s-c)}}$

= $\inline {\color{Black}\sqrt{42(12)(28)(2)}}$ = 168sq m

area of parallelogram ABCD = 2 x 168 = 336 sq m

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Filed Under: Area - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

21 9412

Q:

If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.

A) 110	B) 120
C) 130	D) 140

Answer & Explanation Answer: B) 120

Explanation:

let length = x and breadth = y then

2(x+y) = 46 $\Rightarrow$ x+y = 23

x²+y² = 17² = 289

now (x+y)² = 23²

$\Rightarrow$ x²+y²+2xy= 529

289+ 2xy = 529

$\Rightarrow$ xy = 120

area = xy = 120 sq.cm

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Filed Under: Area - Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

28 9304

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