# Bank PO Questions

Q:

A watch which gains uniformly ,is 5 min,slow at 8 o'clock in the morning on sunday and it is 5 min 48 sec.fast at 8 p.m on following sunday. when was it correct?

 A) 7pm on wednesday B) 20 min past 7pm on wednesday C) 15min past 7pm on wednesday D) 8pm on wednesday

Explanation:

This sunday morning at 8:00 AM, the watch is 5 min. Slow, and the next sunday at 8:00PM it becomes 5 min 48 sec fast.  The watch gains $\inline \fn_jvn \small 5+5\tfrac{48}{60}$ min in a time of  (7×24)+12 = 180 hours.

To show the correct time, it has to gain 5 min.

$\inline \fn_jvn \frac{54}{5}min\rightarrow 180 \; hours$

$\inline \fn_jvn 5\; min\rightarrow ?$

$\inline \fn_jvn \Rightarrow \frac{5}{\frac{54}{5}}\times 180$

$\inline \fn_jvn 83\frac{1}{3}hrs =72hrs+11\frac{1}{3}hrs=3days+11hrs+20min$

So the correct time will be shown on wednesday at 7:20 PM

25 8437
Q:

How many cubes of 3cm edge can be cut out of a cube of 18cm edge

 A) 36 B) 232 C) 216 D) 484

Explanation:

number of cubes=(18 x 18 x 18) / (3 x 3 x 3) = 216

44 8165
Q:

A sum of money amounts to Rs.6690 after 3 years and to Rs.10,035 after 6 years on compound interest.find the sum.

 A) 4360 B) 4460 C) 4560 D) 4660

Explanation:

Let the sum be Rs.P.then
P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(ii)
On dividing,we get (1+R/100)^3=10025/6690=3/2.
Substituting this value in (i),we get:
P*(3/2)=6690 or P=(6690*2/3)=4460
Hence,the sum is rs.4460.

26 7991
Q:

If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.

 A) 110 B) 120 C) 130 D) 140

Explanation:

let length = x and breadth = y then

2(x+y) = 46  $\inline \fn_cm \Rightarrow$  x+y = 23

x²+y² = 17² = 289

now (x+y)² = 23²

$\inline \fn_cm \Rightarrow$x²+y²+2xy= 529

289+ 2xy = 529

$\inline \fn_cm \Rightarrow$ xy = 120

area = xy = 120 sq.cm

26 7816
Q:

The length of a rectangular hall is 5m more than its breadth. The area of the hall is 750 m. The length of the hall is

 A) 20 B) 25 C) 30 D) 35

Explanation:

Then, length = (x+5)m

x(x+5) = 750

x² + 5x - 750= 0

(x+30)(x-25)= 0

x = 25