# Bank PO Questions

Q:

How many cubes of 3cm edge can be cut out of a cube of 18cm edge

 A) 36 B) 232 C) 216 D) 484

Explanation:

number of cubes=(18 x 18 x 18) / (3 x 3 x 3) = 216

41 6715
Q:

A watch which gains 5 seconds in 3 minutes was set right at 7 a.m. In the afternoon of the same day, when the watch indicated quarter past 4 o'clock, the true time is:

 A) 4pm B) 5pm C) 6pm D) 7pm

Explanation:

Time from 7 am to 4.15 pm  = 9 hrs 15 min = $\inline \frac{37}{4}$ hrs

3 min. 5 sec. of this clock = 3 min. of the correct clock.

Now 3min.5sec. is$\inline \frac{37}{720}$ hrs of this clock = 3 min.is$\inline \frac{1}{20}$ hrs of the correct clock

$\inline \frac{37}{4}$ hrs of clock = $\inline (\frac{1}{20}\times \frac{720}{37}\times \frac{37}{4})$ hrs of the correct clock.

= 9 hrs of the correct clock.

$\inline \therefore$ The correct time is 9 hrs after 7 am. i.e., 4 pm.

28 6154
Q:

At what time between 5 and 6 o' clock are the hands of a 3 minutes apart ?

 A) 24min B) 12min C) 13min D) 14min

Explanation:

In this type of problems the formuae is
(5*x+ or - t)*12/11
Here x is replaced by the first interval of given time. Here x is 5.
t is spaces apart

Case 1 : (5*x + t) * 12/11

(5*5 + 3) * 12/11

28 * 12/11 = 336/11= $\inline 31\frac{5}{11}$ min

therefore the hands will be 3 min apart at 31 5/11 min past 5.

Case 2 : (5*x - t) * 12/11

(5*5 -3 ) * 12/11

22 *12/11 = 24 min

therefore the hands will be 3 min apart at 24 min past 5

17 5902
Q:

A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is

 A) Rs. 258 B) Rs. 358 C) Rs. 458 D) Rs. 558

Explanation:

Area to be plastered = $\inline [2(l+b)\times h]+(l\times b)$

=$\inline [2(25+12)\times 6]+(25\times 12)=744\; sq\: m$

Cost of plastering = $\inline 744\times \frac{75}{100}=Rs.558$

24 5876
Q:

What annual payment will discharge a debt of Rs.7620 due in 3years at$\inline 16\frac{2}{3}$ % per annum interest?

 A) 5430 B) 4430 C) 3430 D) 2430

Explanation:

Let each installment be Rs.x. Then,

(P.W. of Rs.x due 1 year hence) + (P.W of Rs.x due 2 years hence) + (P.W of Rs. X due 3 years hence) = 7620.$\inline \left [ \frac{x}{1+(\frac{50}{3\times 100})} \right ]+\left [ \frac{x}{1+(\frac{50}{3\times 100})^2} \right ]+\left [ \frac{x}{1+(\frac{50}{3\times 100})^3} \right ]=7620$

$\inline \frac{6x}{7}+\frac{36x}{49}+\frac{216x}{343}=7620$

$\inline 294x+252x+216x=7620\times 343$

$\inline \fn_jvn \Rightarrow x=3430$

Amount of each installment = Rs.3430