Bank PO Questions


Q:

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: C) 3

Explanation:

Area of the park = (60 x 40) = 2400m2

Area of the lawn = 2109m2 

Area of the crossroads = (2400 - 2109) = 291m2 

Let the width of the road be x metres. Then,

60x+40x-X2=291 

x2-100x+291=0 

  (x - 97)(x - 3) = 0
   x = 3.

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17 15502
Q:

A sum of money amounts to Rs.6690 after 3 years and to Rs.10,035 after 6 years on compound interest.find the sum.

A) 4360 B) 4460
C) 4560 D) 4660
 
Answer & Explanation Answer: B) 4460

Explanation:

Let the sum be Rs.P.then
P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(ii)
On dividing,we get (1+R/100)^3=10025/6690=3/2.
Substituting this value in (i),we get:
P*(3/2)=6690 or P=(6690*2/3)=4460
Hence,the sum is rs.4460.

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45 15149
Q:

The difference between compound interest and simple interest on a sum for two years at 8% per annum, where the interest is compounded annually is Rs.16. if the interest were compounded half yearly , the difference in two interests would be nearly

A) Rs.24.64 B) Rs.21.85
C) Rs.16 D) Rs.16.80
 
Answer & Explanation Answer: A) Rs.24.64

Explanation:

For 1st year S.I =C.I.

 

Thus, Rs.16 is the S.I. on S.I. for 1 year, which at 8% is thus Rs.200

 

i.e S.I on the principal for 1 year is Rs.200

 

Principle = Rs.100*2008*1 = Rs.2500

 

Amount for 2 years, compounded half-yearly

 Rs.2500*1+41004=Rs.2924.4

 

C.I = Rs.424.64

 

Also, S.I=Rs.2500*8*2100=Rs.400

 

Hence, [(C.I) - (S.I)] = Rs. (424.64 - 400) = Rs.24.64

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24 15091
Q:

Find the ratio of the areas of the incircle and circumcircle of a square.

A) 1:1 B) 1:2
C) 1:3 D) 1:4
 
Answer & Explanation Answer: B) 1:2

Explanation:

Let the side of the square be x. Then, its diagonal = 2x2=2x 

Radius of incircle = x2 

Radius of circum circle= 2×x2=x2 

Required ratio = πx24:πx22=14:12=1:2

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36 15060
Q:

At what rate percent per annum will a sum of money double in 8 years.

A) 12.5% B) 13.5%
C) 11.5% D) 14.5%
 
Answer & Explanation Answer: A) 12.5%

Explanation:

Let principal = P, Then, S.I.= P and Time = 8 years

We know that S.I. = PTR/100

Rate = [(100 x P)/ (P x 8)]% = 12.5% per annum.

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37 14752
Q:

One side of a rectangular field is 15m and one of its diagonal is 17m. Find the area of field?

A) 110 B) 120
C) 130 D) 140
 
Answer & Explanation Answer: B) 120

Explanation:

Other side = [(17 x 17) - (15 x 15)] = (289 - 225) = 8m
Area = 15 x 8 =120 sq. m

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43 14551
Q:

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A) 20% B) 30%
C) 40% D) 50%
 
Answer & Explanation Answer: D) 50%

Explanation:

Let original length = x and original breadth = y.

Original area = xy. 

New length = x/2 and New breadth=3y 

New area = 32xy 

Therefore,  Increase in area = New area-original area = 32xy-xy=12xy 

 

Therefore,  Increase % = increase in area original area*100=12xyxy*100=50 %

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14 13457
Q:

What is the rate of interest p.c.p.a.?

I. An amount doubles itself in 5 years on simple interest.

II. Difference between the compound interest and the simple interest earned on a certain amount in 2 years is Rs. 400.

III. Simple interest earned per annum is Rs. 2000

A) I only B) II and III only
C) All I, II and III D) I only or II and III only
 
Answer & Explanation Answer: D) I only or II and III only

Explanation:

I.P*R*5100=PR=20

 II.P1+R1002-P-P*R*2100=400=>pR2=4000000

 III.P*R*1100=2000=>PR=200000

 PR2PR=4000000200000R=20

 

Thus I only or (II and III) give answer.

 

 Correct answer is (D)

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