# Bank PO Questions

Q:

A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be

 A) 7744 B) 8844 C) 5544 D) 4444

Explanation:

length of wire = ${\color{Blue}2&space;\Pi&space;r}$= 2 *(22/7 )*56 = 352 cm
side of the square = 352/4 = 88cm
area of the square = 88*88 = 7744sq cm

19 7217
Q:

If log 2 = 0.30103, Find the number of digits in 256 is

 A) 17 B) 19 C) 23 D) 25

Explanation:

${\color{Black}\log&space;(2^{56})=(56\times0.30103)&space;}$ =16.85768.

Its characteristics is 16.

Hence, the number of digits in ${\color{Black}2^{56}&space;}$ is 17.

15 7188
Q:

At what time between 5 and 6 o' clock are the hands of a 3 minutes apart ?

 A) 24min B) 12min C) 13min D) 14min

Explanation:

In this type of problems the formuae is
(5*x+ or - t)*12/11
Here x is replaced by the first interval of given time. Here x is 5.
t is spaces apart

Case 1 : (5*x + t) * 12/11

(5*5 + 3) * 12/11

28 * 12/11 = 336/11= $\inline 31\frac{5}{11}$ min

therefore the hands will be 3 min apart at 31 5/11 min past 5.

Case 2 : (5*x - t) * 12/11

(5*5 -3 ) * 12/11

22 *12/11 = 24 min

therefore the hands will be 3 min apart at 24 min past 5

18 7136
Q:

The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is

 A) 49 B) 154 C) 378 D) 1078

Explanation:

The diameter is equal to the shortest side of the rectangle.

$\inline \therefore$ $\inline area\: of\: circle= \prod r^{2}=\frac{22}{7}\times 49=154 \: cm^{2}$

10 7030
Q:

A watch which gains 5 seconds in 3 minutes was set right at 7 a.m. In the afternoon of the same day, when the watch indicated quarter past 4 o'clock, the true time is:

 A) 4pm B) 5pm C) 6pm D) 7pm

Explanation:

Time from 7 am to 4.15 pm  = 9 hrs 15 min = $\inline \frac{37}{4}$ hrs

3 min. 5 sec. of this clock = 3 min. of the correct clock.

Now 3min.5sec. is$\inline \frac{37}{720}$ hrs of this clock = 3 min.is$\inline \frac{1}{20}$ hrs of the correct clock

$\inline \frac{37}{4}$ hrs of clock = $\inline (\frac{1}{20}\times \frac{720}{37}\times \frac{37}{4})$ hrs of the correct clock.

= 9 hrs of the correct clock.

$\inline \therefore$ The correct time is 9 hrs after 7 am. i.e., 4 pm.