1
Q:

If, then xyz is equal to :

A) 0 B) 1
C) lmn D) 2

Answer:   B) 1



Explanation:

 \inline \frac{\log x}{l+m-2n}=\frac{\log y}{m+n-21}=\frac{\log z}{n+l-2m}=k(say)

 \Rightarrow        \inline \log x = k(l+m-2n)           --------(1)

             \inline \log y=k(m+n-2l)           ---------(2)

            \inline \log z=k(n+l-2m)             --------(3)

\therefore  \inline \log x+\log y+\log z = k(l+m-2n)+k(m+n-2l)+k(n+l-2m)

             \inline \log (xyz)=0

\inline \Rightarrow        \inline \log xyz=\log 1

\inline \Rightarrow             xyz = 1

Q:

Solve the equation   ?

A) -1/2 B) 1/2
C) 1 D) -1
 
Answer & Explanation Answer: A) -1/2

Explanation:

Rewrite equation as

Leads to 2x + 1 = 0 

Solve for x : x = -1/2

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3 192
Q:

If  = m, then  is equal to ?

A) 1/(1+2m) B) (1+2m)/2
C) 2m/(2m+1) D) (2m+1)/2m
 
Answer & Explanation Answer: B) (1+2m)/2

Explanation:

=
=

.

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6 420
Q:

If  , then 

A) 1 B) 2
C) 4 D) 8
 
Answer & Explanation Answer: B) 2

Explanation:

Given  

Now  = 

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7 437
Q:

If log 64 = 1.8061, then the value of log 16 will be (approx)?

A) 1.9048 B) 1.2040
C) 0.9840 D) 1.4521
 
Answer & Explanation Answer: B) 1.2040

Explanation:

Given that, 

 

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11 1050
Q:

A fast moving superfast express crosses another pasenger train in 20 seconds. The speed of faster train is 72 km/hr and speeds of slower train is 27 km/h. Also the length of faster ntrain is 100m, then find the length of the slower train if they are moving in the same direction.

A) 100 m B) 125 m
C) 150 m D) 175 m
 
Answer & Explanation Answer: C) 150 m

Explanation:

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14 1091