0
Q:

# A Shepherd had n goats in the year 2000. In 2001 the no.of goats increased by 40% . In 2002 the no. of goats declined to 70%. In 2003 the no. of  goats grew by 30%. In 2004, he sold 10% goats, then he had only 34,398 goats. The percentage increase of the no.of goats in this duration was:

 A) 14.66% B) 16.66% C) 20% D) 33.33%

Explanation:

There is no need to use the no of goats i.e (34,398). let initially thete be 1000 goats then

1000 -----> 1400 -----> 980 -----> 1274 ----->1146.6

Thus the % increase = $\inline&space;\frac{1146.6-1000}{1000}\times&space;100$ = 14.66%

Q:

The price of a car is increased by 25%, by how much percent, must the new price of this car be decreased to restore its original price ?

 A) 20% B) 24% C) 21% D) 25%

Explanation:

Suppose that the original price of the car = Rs. x

Then new price of the car

=> (x) + (×25/100) Rs. 5x/

To restore the original price, the new price must be decreased by

5x/− x/4

So required percentage =(x/4)/(5x/4) × 100%

= 20%

3 50
Q:

Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the amount invested in Scheme X and 240% of the amount invested in Scheme Y, what was the amount invested in Scheme Y by Prasanna ?

 A) Rs.6000 B) Rs.4500 C) Rs.7500 D) Rs.5000

Explanation:

Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then,

As we know:

Simple interest (S.I.) = PTR/100

(a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200

= 10a + 12b + 15c = 320000 .........(1)

Now, c = 240% of b = 12b/5 .........(2)

And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3)

From (1), (2) and (3), we have

16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000

∴ Sum invested in Scheme Y = Rs.5000.

2 22
Q:

A man reduces his travelling time by a fraction of 2/5, as a result the distance covered by the man is increased by 20%, find the percentage increase in the speed of the man ?

 A) 77% B) 88% C) 100% D) 99%

Explanation:

3 39
Q:

60 percent of 2/7 of three-fourth of a number is 2664. What is the number ?

 A) 20720 B) 21352 C) 25421 D) 24150

Explanation:

Let N be the required number.

=> $\inline \fn_jvn \frac{60}{100}x\frac{2}{7}x\frac{3}{4}xN = 2664$

=> N = 2664x2x7x5/9

=> N = 20720.

8 208
Q:

At an examination in which maximum marks are 500. K got 10% less than L, L got 25% more than M and M got 20% less than N. If K got 360 marks what percentage of marks was obtained by N ?

 A) 80 B) 87 C) 78 D) 76

Explanation:

Let marks obtained by N = x

M's marks = 0.80x

L's marks = 1.25 (0.80x)

K's marks = (0.90) (1.25) (0.80x)

= 0.9x

But 0.9x = 360 ⇒ x = 400

Percentage of Marks obtained by N

= 400 x 100/500 = 80%