Permutations and Combinations Question & Answers
5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible?
|A) 2880||B) 1440|
|C) 720||D) 2020|
There are total 9 places out of which 4 are even and rest 5 places are odd.
4 women can be arranged at 4 even places in 4! ways.
and 5 men can be placed in remaining 5 places in ways.
Hence, the required number of permutations = 4! x = 24 x 120 = 2880
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