A) 14.4 sec | B) 15.5 sec |

C) 18.8 sec | D) 20.2 sec |

Explanation:

Let the length of the train be L metres

Speed of first train = m/hour

Speed of secxond train = m/hour

When running in opposite directions, relative speed = 200 L + 300 L m/hour

Distance to be covered = L + L = 2L metre

Time taken = sec

=14.4 sec

A) 140 kms | B) 120 kms |

C) 96 kms | D) 142 kms |

Explanation:

It is given train X leave station A at 6:30 am, here it is asked to calculate the distance from A when the trains meet, the

Distance traveled by train left at 6:30 am upto 7:40 am i.e. in 1 hr. 10 min. or 7/6 hours = 30 x 7/6 = 35 km

So train leaving at 7:40 am will meet first train after covering a distance of 35 km. with relative speed of 40-30=10 km/hr.

Hence time taken = 35/10 = 3.5 hours or 3 hours 30 minutes

So distance from A = Distance traveled by 2nd train in 3 hr. 30 min

= 40 x 3.5 = 140 km.

A) 60 sec | B) 48 sec |

C) 45 sec | D) 34 sec |

Explanation:

Relative speed = 42 + 36 = 78 km/hr = m/s

Distance = (520 + 520) =1040 mts.

Time = = 48 sec

A) Option A | B) Option B |

C) Option C | D) Option D |

Explanation:

As Trains are moving in same direction,

Relative Speed = 60-20 = 40 kmph

m/sec

Length of Train= Speed * Time

Length =

A) 355 mts | B) 325 mts |

C) 365 mts | D) 312 mts |

Explanation:

Given speed = 63 km/hr = m/s

Let the length of the bridge = x mts

Given time taken to cover the distance of (170 + x)mts is 30 sec.

We know speed = m/s

x = 355 mts.

A) 90 mts | B) 150 mts |

C) 120 mts | D) 100 mts |

Explanation:

We know that

distance= speed * time

d =

d= 100 mts.