A) 14.4 sec | B) 15.5 sec |

C) 18.8 sec | D) 20.2 sec |

Explanation:

Let the length of the train be L metres

Speed of first train = m/hour

Speed of secxond train = m/hour

When running in opposite directions, relative speed = 200 L + 300 L m/hour

Distance to be covered = L + L = 2L metre

Time taken = sec

=14.4 sec

A) 2:1 | B) 3:2 |

C) 4:3 | D) 5:4 |

Explanation:

Note : If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then: (A's speed) : (B's speed) = (b : a)

Therefore, Ratio of the speeds of two trains = = 3 : 2

A) 60 | B) 62 |

C) 64 | D) 65 |

Explanation:

Relative speed = m / sec = kmph = 112 kmph.

Speed of goods train = (112 - 50) kmph = 62 kmph.

A) 10 | B) 25 |

C) 12 | D) 20 |

Explanation:

Speed of train 1 = = 12 m/sec

Speed of train 2 = = 8 m/sec

if they travel in opposite direction, relative speed = 12 + 8 = 20 m/sec

distance covered = 120 + 120 = 240 m

time = distance/speed = 240/20 = 12 sec

A) 48 sec | B) 36 sec |

C) 18 sec | D) 72 sec |

Explanation:

Speed of the train relative to jogger = (45-9) km/hr = 36 km/hr

= = 10 m/sec

Distance to be covered =(240 + 120)m = 360 m

Time taken = sec = 36 sec

A) 500 | B) 400 |

C) 360 | D) 480 |

Explanation:

Speed of train 1 = 48 kmph

Let the length of train 1 = 2x meter

Speed of train 2 = 42 kmph

Length of train 2 = x meter (because it is half of train 1's length)

Distance = 2x + x = 3x

Relative speed= 48+42 = 90 kmph = m/s = 25 m/s

Time = 12 s

Distance/time = speed

Length of the first train = 2x = 200 meter

Time taken to cross the platform= 45 s

Speed of train 1 = 48 kmph = 480/36 = 40/3 m/s

Distance = 200 + y [where y is the length of the platform]