A) 2:1 | B) 3:2 |

C) 4:3 | D) 5:4 |

Explanation:

Note : If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then: (A's speed) : (B's speed) = (b : a)

Therefore, Ratio of the speeds of two trains = = 3 : 2

A) 6.24 sec | B) 6.58 sec |

C) 7.325 sec | D) 7.65 sec |

Explanation:

Here total distance = 154 + 101 = 255 mts

Given speed = 120 kmph = 120x5/18 m/sec

Hence, Time = d/s = 255x18/120x5 = 7.65 sec

A) 240 mts | B) 270 mts |

C) 260 mts | D) 250 mts |

Explanation:

Relative speed = 120 + 80 = 200 km/hr.

= 200 x 5/18 = 500/9 m/sec.

Let the length of the other train be L mts.

Then, (L + 260)/9 = 500/9 => L = 240 mts.

A) 49 kmph | B) 50 kmph |

C) 51 kmph | D) 52 kmph |

Explanation:

Speed of the train relative to man

= (125/10) m/sec = (25/2) m/sec.

[(25/2) x (18/5)] km/hr = 45 km/hr.

Let the speed of the train be 'x' km/hr.

Then, relative speed = (x - 4) km/hr.

x - 4 = 45 => x = 49 km/hr.

A) 42 sec | B) 44 sec |

C) 46 sec | D) 48 sec |

Explanation:

Relative speed = 60 + 90 = 150 km/hr.

= 150 x 5/18 = 125/3 m/sec.

Distance covered = 1.10 + 0.9 = 2 km = 2000 m.

Required time = 2000 x 3/125 = 48 sec.

A) 170 m | B) 100 m |

C) 270 m | D) 320 m |

Explanation:

Relative speed = (72 - 36) x 5/18 = 2 x 5 = 10 mps.

Distance covered in 32 sec = 32 x 10 = 320 m.

The length of the faster train = 320 m.