A) 2:1 | B) 3:2 |

C) 4:3 | D) 5:4 |

Explanation:

Note : If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then: (A's speed) : (B's speed) = (b : a)

Therefore, Ratio of the speeds of two trains = = 3 : 2

A) 80 kms | B) 60 kms |

C) 45 kms | D) 32 kms |

Explanation:

Let 'd' be the distance and 's' be the speed and 't' be the time

d=sxt

45 mins = 3/4 hr and 48 mins = 4/5 hr

As distance is same in both cases;

s(3/4) = (s-5)(4/5)

3s/4 = (4s-20)/5

15s = 16s-80

s = 80 km.

=> d = 80 x 3/4 = 60 kms.

A) 15:07 hrs | B) 15:20 hrs |

C) 15:05 hrs | D) 15:00 hrs |

Explanation:

Next train comes at 17:00 hrs.

So, last train will be = 17:00hrs - 2:30hrs

= 14:30hrs

Announcement made after 37 min of the last train.

S0, 14:30hrs + 00:37 min

= 15:07 hrs.

A) 4/3 hrs | B) 2/3 hrs |

C) 3/2 hrs | D) 1/4 hrs |

Explanation:

Let the original speed and time is S and T

then distance = S x T

Now the speed changes to 2/3S and T is T+20

As the distance is same

S x T = 2/3Sx(T+20)

solving this we get t = 40 minutes

=40/60 = 2/3 hour

A) 60 mts | B) 120 mts |

C) 240 mts | D) 360 mts |

Explanation:

Speed of the Train K is given by s = d/t = 240/20 = 12 m/s

Distance covered by Train K in 50 seconds = 12 x 50 = 600 mts.

But it crosses Train L in 50 seconds

Therefore, the length of the Train L is = 600 - 240 = 360 mts.

A) 33 sec | B) 37.33 sec |

C) 36.43 sec | D) 32 sec |

Explanation:

Speed = 108 km/hr

enter a tunnel,, means that the train covers a distance equal to its own length

so (108 x 5/18) = x/4 where x= length of train

hence x = 120 mtrs

to pass completely train has to travel a distance = (x + tunnel length) that is 1120 mtrs.

so (1120/t) = (108x5/18)

t = 37.33 sec