A) 2:1 | B) 3:2 |

C) 4:3 | D) 5:4 |

Explanation:

Note : If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then: (A's speed) : (B's speed) = (b : a)

Therefore, Ratio of the speeds of two trains = = 3 : 2

A) 140 kms | B) 120 kms |

C) 96 kms | D) 142 kms |

Explanation:

It is given train X leave station A at 6:30 am, here it is asked to calculate the distance from A when the trains meet, the

Distance traveled by train left at 6:30 am upto 7:40 am i.e. in 1 hr. 10 min. or 7/6 hours = 30 x 7/6 = 35 km

So train leaving at 7:40 am will meet first train after covering a distance of 35 km. with relative speed of 40-30=10 km/hr.

Hence time taken = 35/10 = 3.5 hours or 3 hours 30 minutes

So distance from A = Distance traveled by 2nd train in 3 hr. 30 min

= 40 x 3.5 = 140 km.

A) 60 sec | B) 48 sec |

C) 45 sec | D) 34 sec |

Explanation:

Relative speed = 42 + 36 = 78 km/hr = m/s

Distance = (520 + 520) =1040 mts.

Time = = 48 sec

A) Option A | B) Option B |

C) Option C | D) Option D |

Explanation:

As Trains are moving in same direction,

Relative Speed = 60-20 = 40 kmph

m/sec

Length of Train= Speed * Time

Length =

A) 355 mts | B) 325 mts |

C) 365 mts | D) 312 mts |

Explanation:

Given speed = 63 km/hr = m/s

Let the length of the bridge = x mts

Given time taken to cover the distance of (170 + x)mts is 30 sec.

We know speed = m/s

x = 355 mts.

A) 90 mts | B) 150 mts |

C) 120 mts | D) 100 mts |

Explanation:

We know that

distance= speed * time

d =

d= 100 mts.