A) Rs 1 | B) Rs 1.33 |

C) Rs 1.5 | D) Rs 1.6 |

Explanation:

Recall it is based on inverse proportion or product constancy concept.

Reducion in price increase in amount

25% 33.33% = 4 oranges

It means original number of oranges = 4 x 3 = 12

original price of oranges = = Rs. 1.33

A) 97 % | B) 110 % |

C) 135 % | D) 115 % |

Explanation:

% Profit with respect to A = 40 + 50 + (40 x 50)/100 = 90 + 20 = 110 %.

A) 1.44% loss | B) 14.4% loss |

C) 0% | D) 14.4% profit |

Explanation:

SP of each car is Rs. 325475, he gains 12% on first car and losses 12% on second car.

In this case, there will be loss and percentage of loss is given by

= [(profit%)(loss%)]/100 = (12)(12)/100 % = 1.44%

A) 4% p.a. | B) 6% p.a. |

C) 8% p.a. | D) 12% p.a. |

Explanation:

If the interest earned is 25% more than the earlier interest then the rate of interest also should be 25% higher than the earlier rate.

Let the earlier rate of interest be x%.

Now it will be (x + 3)%

% increase = (x + 3) - x/x * 100 = 25

=> x = 12%

A) Rs. 17.80 | B) Rs. 16.30 |

C) Rs. 14 | D) Rs. 15.40 |

Explanation:

C.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.

A) 68% | B) 80% |

C) 75% | D) 100% |

Explanation:

When 3 passengers income was 3x

expense= Rs.30

profit =20% of 30 = Rs.6

That means his earning is Rs.36. so that per passenger fare must be Rs.12.

When 4 passengers

earning = 12x4=Rs.48.

expense =Rs.24.

profit = Rs.24 = 100%