A) Rs 1 | B) Rs 1.33 |

C) Rs 1.5 | D) Rs 1.6 |

Explanation:

Recall it is based on inverse proportion or product constancy concept.

Reducion in price increase in amount

25% 1/4 1/3 33.33% = 4 oranges

It means original number of oranges = 4 x 3 = 12

original price of oranges = 16/12 = Rs. 1.33

A) 33.33% | B) 29.97% |

C) 25% | D) 22.22% |

Explanation:

Let 'A' be the cost price of property P1.

Then from the given data, the selling price of P1 = Rs. 1,00,000

He got 20% loss on selling P1

$\mathbf{\Rightarrow}\mathbf{A}\mathbf{}\mathbf{-}\mathbf{}\frac{\mathbf{20}\mathbf{A}}{\mathbf{100}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{100000}\phantom{\rule{0ex}{0ex}}\mathbf{\Rightarrow}\mathbf{A}\mathbf{}\mathbf{=}\mathbf{}\mathbf{1}\mathbf{,}\mathbf{25}\mathbf{,}\mathbf{000}$

Therefore, the amount he lossed on selling P1 = 25,000

As ge he got no loss or gain on sale of P1 and P2, the gain on selling P2 = 25,000

But the selling price of P2 = 1,00,000 => Cost price of P2 = 75,000

Hence, the profit percentage on P2 = $\frac{\mathbf{Gain}}{\mathbf{CP}}\mathbf{x}\mathbf{}\mathbf{100}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{25000}}{\mathbf{75000}}\mathbf{x}\mathbf{100}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{100}}{\mathbf{3}}\mathbf{=}\mathbf{}\mathbf{33}\mathbf{.}\mathbf{33}\mathbf{\%}$

A) Rs. 3680 | B) Rs. 3560 |

C) Rs. 3320 | D) Rs. 3250 |

Explanation:

Let the Cost price of the powerbank = Rs. P

But given that by selling it at Rs. 1950, it gives a loss of 25%

=> $\frac{\mathbf{P}\mathbf{}\mathbf{x}\mathbf{}\mathbf{75}}{\mathbf{100}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{1950}$

=>$\mathbf{P}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{1950}\mathbf{}\mathbf{x}\mathbf{}\mathbf{100}}{\mathbf{75}}$ = **Rs. 2600**

Now, to get a profit of 25%

Selling Price = $\frac{\mathbf{2600}\mathbf{}\mathbf{x}\mathbf{}\mathbf{125}}{\mathbf{100}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{Rs}\mathbf{.}\mathbf{}\mathbf{3250}$.

A) Rs. 7.46/kg | B) Rs. 8/kg |

C) Rs. 8.74/kg | D) Rs. 8.56/kg |

Explanation:

Let the selling price of the rice = Rs.P/kg

Now, according to the question,

1040 - 100p = 30p

=> p = 8/kg

Hence, the selling price of the rice = **Rs. 8/kg**

A) 20 | B) 24 |

C) 26 | D) 28 |

Explanation:

Let the total amount be **200** {L.C.M of 40 and 50}

Chacobar C.P. = 200/50 = **4**

Fivestar C.P = 200/40 = **5**

Remaining Money after petrol = [200 - 200×10%] = **180**

Remaining money after buying fivestars = [180 - 20×5] = **80**

So number of Chacobar she can buy =** 80/4 = 20**

A) 13% | B) 8.5% |

C) 9.5% | D) 11.25% |

Explanation:

The ratio of money she lended is

24000 : 16000 = 3 : 2

Let the rate of interest be R%

**8% R%**** **

** 10**

**3 : 2**

**R = 13%.**

A) 260/11% | B) 18.4% |

C) 22.5% | D) 100/7% |

Explanation:

When profit is calculated on Marked Price (M.P) then,

**C.P = M.P - P%**

Let M.P = 100

=> C.P = 100 - 30 = 70

But S.P = Rs. 80 as he gave 20% discount,

Now, Actual Profit = $\frac{80-70}{70}x100$

= **100/7 % **

A) Rs. 12,500 | B) Rs. 11,250 |

C) Rs. 12,750 | D) Rs. 11,680 |

Explanation:

Given that SP = Rs. 12000 - 10% = Rs. 10,800

Loss% = 4

We know that, **C.P = 100/(100 - Loss%) x 100**

=> 100/100-4 x 10800

=> 1080000/96

**C.P = Rs. 11,250**

A) 13.8 % | B) 11.4 % |

C) 12.5 % | D) 14.5 % |

Explanation:

10% profit at half plot = 600000/2 x 10/100 = Rs. 30,000

15% profit at remaining half plot = 600000/2 x 15/100 = Rs. 45,000

Now, total profit = 30000 + 45000 = 75000

Profit % = 75000/600000 x 100 = **12.5 %**