probability Search

Q:

Statements followed by some conclusions are given below.

Statements:
1. A bag has 2 white, 3 black, 4 red and 6 green balls.
2. 2 balls are selected at random from the bag.

Conclusions:
1. The probability that a black ball is selected is 1/5.
2. The probability that a red ball is selected is 6/15.

Find which of the conclusions logically follows from the given statements.

A) Only conclusion 1 follows	B) Only conclusion 2 follows
C) Both 1 and 2 follow	D) Neither 1 nor 2 follows

Answer & Explanation Answer: A) Only conclusion 1 follows

Explanation:

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Filed Under: Statement and Conclusions
Exam Prep: Bank Exams

Q:

Two boxes contain 4 and 16 balls respectively. Two balls in the first box and four in the second, are black. If a box is chosen randomly and two balls are drawn at random from it, what is the
probability that at least one ball is black if the ball is not replaced?

A) 11/20	B) 43/120
C) 77/120	D) 9/20

Answer & Explanation Answer: C) 77/120

Explanation:

At least one black can be chosen in two ways from each box:
Now, probability of choosing at least one black ball from first box

= 1/2 × [ (2C1× 2C1)/4C2 + 2C2/ 4C2 ]= 5/12

Probability of choosing at least one black ball from 2nd box
= 1/2 × [(4C1×12C1)/16C2 + 4C2/ 16C2] = 9/40

Final probability

= 5/12 + 9/40 = (50 + 27)/120 = 77/120

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

Q:

In a bag which contains 40 balls, there are 18 red balls and some green and blue balls. If two balls are picked up from the bag without replacement, then the probability of the first ball being red and second being green is 3/26. Find the number of blue balls in the bag.

A) 16	B) 12
C) 10	D) 14

Answer & Explanation Answer: B) 12

Explanation:

Total balls = 40

Red balls = 18

Let green balls are x

Then, (18/40) × (

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT

Q:

If two marbles are picked at random, what is the probability that either both are red or both are green?

A) 5/7	B) 5/14
C) 1/7	D) 1/14

Answer & Explanation Answer: C) 1/7

Explanation:

Required probability = $\frac{(10 + 3)}{91} = \frac{13}{91} = \frac{1}{7}$

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE
Job Role: Bank Clerk , Bank PO

Q:

Study the information carefully to answer the following questions: An urn contains 5 red, 3 green, 2 blue and 4 yellow marbles. If three marbles are picked at random, what is the probability that one is green and two are yellow?

A) 3/14	B) 2/91
C) 9/182	D) 7/545

Answer & Explanation Answer: C) 9/182

Explanation:

Required probability = $\frac{3 \times 6}{364} = \frac{9}{182}$

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE
Job Role: Bank Clerk , Bank PO

Q:

From a pack of 52 cards, 3 cards are drawn together atrandom, What is the probability of both the cards are king?

A) 1/5225	B) 1/5525
C) 5525	D) 1/525

Answer & Explanation Answer: B) 1/5525

Explanation:

n(S) = 52C3 = 132600/6 = 22100

n(E) = 4C3 = 24/6 = 4

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Filed Under: Permutations and Combinations

Q:

A box contains 5 green, 4 yellow and 3 white marbles. Threemarbles are drawn at random. What is the probability thatthey are not of the same colour ?

A) 40/44	B) 44/41
C) 41/44	D) 40/39

Answer & Explanation Answer: C) 41/44

Explanation:

n(E) = 5C3 + 4C3 + 3C3 = 10 + 4 + 1 = 15n(S) = 12C3 = 220

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Filed Under: Permutations and Combinations
Exam Prep: Bank Exams

Q:

In a single throw with 2 dices, what is probability of neither getting an even number on one and nor a multiple of 3 on other?

A) 11/36	B) 25/36
C) 5/6	D) 1/6

Answer & Explanation Answer: B) 25/36

Explanation:

We first calculate the probability of getting an even number on one and a multiple of 3 on other,Here, n(s) = 6x6 = 36 and

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