3
Q:

$\inline \frac{7}{8}\: of\: 448 +\frac{6}{7}\: of\: 3374 = ?$

 A) 3084 B) 3184 C) 3584 D) None of these

Explanation:

$\inline \frac{7}{8}\times 448 +\frac{6}{7}\times 3374 = 392+2892=3284$

Q:

An owner of a Dry fruits shop sold small packets of mixed nuts for Rs. 150 each and large packets for Rs. 250 each. One day he sold 5000 packets, for a total of Rs. 10.50 lakh. How many small packets were sold ?

 A) 2000 B) 3000 C) 2500 D) 3500

Explanation:

Let 's' be the number of small packets and 'b' the number of large packets sold on that day.

Therefore, s + b = 5000 ... eqn (1)

Each small packet was sold for Rs.150.
Therefore, 's' small packets would have fetched Rs.150s.

Each large packets was sold for Rs.250.
Therefore, 'b' large packets would have fetched Rs.250b.

Total value of sale = 150s + 250b = Rs. 10.5 Lakhs (Given)

Or 150s + 250b = 10,50,000 ... eqn (2)

Multiplying equation (1) by 150, we get 150s + 150b = 7,50,000 ... eqn (3)

Subtracting eqn (3) from eqn (2), we get 100b = 3,00,000
Or b = 3000

We know that s + b = 5000
So, s = 5000 - b = 5000 - 3000 = 2000.

2000 small packets were sold.

4 47
Q:

Simplify the following equation

$\inline \fn_jvn \small \left [ (K-L)^{2}-(K+L)^{2} \right ]/4K = a/b$

 A) K = b /a B) bL = -a C) KL = 1 D) aK = -b

Explanation:

$\inline \fn_jvn \small \left [ (K-L)^{2}-(K+L)^{2} \right ]/4K = a/b$
=> $\inline \fn_jvn \small [K^{2}+L^{2}-2KL-(K^{2}+L^{2}+2KL)]/4K = a/b$

=> - 4KL/4K = a/b

=> L = - a/b

=> bL = -a

2 145
Q:

A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook ?

 A) 15 B) 20 C) 10 D) 8

Explanation:

Let the price of each note book be Rs.x.
Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.
Hence xy = 300
=> y = 300/x
(x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy
=>5(300/x) - 10x - 50 = 0 => $\inline \fn_jvn \small -150+x^{2}+5x=0$
multiplying both sides by -1/10x
=> $\inline \fn_jvn \small x^{2}+15x-10x-150=0$
=> x(x + 15) - 10(x + 15) = 0
=> x = 10 or -15
As x>0, x = 10.

1 229
Q:

A tailor has 37.5 metres of cloth and he has to make 8 pieces out of a metre of cloth. How many pieces can he make out of half of the cloth he has ?

 A) 300 B) 150 C) 175 D) 200

Explanation:

Half of the cloth = 37.5/2
From 1 meter he will make 8 pieces
=> in 37.5/2 ---- ?

37.5/2 x 8

= 150.

1 162
Q:

Identify the greatest numbers :

A.   $\fn_jvn 4^{50}$     B.    $\fn_jvn 2^{100}$    C.   $\fn_jvn 16^{25}$

 A) A B) C C) Both A and B D) All are equal

$\fn_jvn 4^{50}$   =   $\fn_jvn \small (2^{2})^{50}$   =   $\fn_jvn \small 2^{100}$   =>  $\fn_jvn 16^{25}$ =   $\fn_jvn \small (2^{4})^{25}$  =   $\fn_jvn \small 2^{100}$
Hence,  $\fn_jvn 4^{50}$ , $\fn_jvn \small 2^{100}$  and $\fn_jvn 16^{25}$ are all equal.