1
Q:

# Shahrukh starts from Barabanki to Fatehpur , 1 hour after Ajay starts. Shahrukh meets Kajol 1.5 hours after Shahrukh starts. If the speed of Shahrukh is at least 20km/h faster than the speed of Kajol.What is the minimum speed of Shahrukh to overtake Ajay, before he meets Kajol?

 A) 30 B) 40 C) 60 D) None of these

Explanation:

Let t be the time after Kajol starts, when she meets Ajay, then

$\inline&space;t=\frac{300}{(x+y)}$

This should be less than 2.5 or (x+y)>120

Since       y= $\inline&space;\frac{3x}{2}$     $\inline&space;\Rightarrow&space;y>72$

This (y>72) is greater than 67.5 km/h and hence Shahrukh will always overtake Ajay before he meets Kajol.

Q:

Three friends Rudra, Siva and Anvesh start to run around a circular stadium. They complete a revolution in 24, 36 and 30 seconds respectively. After how many minutes will they meet at the starting point ?

 A) 60 B) 120 C) 360 D) 6

Explanation:

For this we have to find the LCM of 24, 36 and 30

LCM of 24, 36 and 30 = 360 sec

360/60 min = 6 minutes.

8 61
Q:

Amith can row a boat d km upstream and the same distance downstream in 5 hours 15 minutes. Also, he can row the boat 2d km upstream in 7 hours. How long will it take to row the same distance 2d km downstream for Amith ?

 A) 4 hrs 10 min B) 3 hrs 15 min C) 3 hrs 30 min D) 4 hrs 1 min

Explanation:

Let the speed of boat and stream be x and y kmph respectively.

According to question

d/x+y + d/x-y = 5h 15m or 21/4 hrs ......(i)

and 2d/x-y = 7...... (ii)

From eq. (i) and (ii)

2d/x+y = 7/2

Hence, Amith will take to row 2d km distance downstream in 7/2 hrs

= 3.5 hrs

= 3 hrs 30 min.

5 130
Q:

Kamal consistently runs 240 meters a day and on Saturday he runs for 400 meters. How many kilometers will he have to run in four weeks ?

 A) 5.75 kms B) 7.36 kms C) 8.2 kms D) 6.98 kms

Explanation:

Total running distance in four weeks = (24 x 240) + (4 x 400)

= 5760 + 1600

= 7360 meters

= 7360/1000

=> 7.36 kms

4 164
Q:

K and L starts walking towards each other at 4 pm at speed of 3 km/hr and 4 km/hr respectively. They were initially 17.5 km apart. At what time do they meet ?

 A) 6:00 am B) 6:30 pm C) 5:45 am D) 5:52 pm

Explanation:

Suppose they meet after 'h' hours

Then

3h + 4h = 17.5

7h = 17.5

h = 2.5 hours

So they meet at => 4 + 2.5 = 6:30 pm

9 263
Q:

P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?

 A) 99 B) 100 C) 89 D) 1

Explanation:

Let, Distance between A and B = d

Distance travelled by P while it meets Q = d + 11

Distance travelled by Q while it meets P = d – 11

Distance travelled by Q while it meets R = d + 9

Distance travelled by R while it meets Q = d – 9

Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11

The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9

But given Ratio of speeds of P & R => P : R = 3 : 2

$\inline \fn_jvn \frac{SP}{SR} = \frac{SP}{SQ}x\frac{SQ}{SR} = \frac{(d+11)(d+9)}{(d-11)(d-9)}$

=> $\inline \fn_jvn \frac{(d+11)(d+9)}{(d-11)(d-9)}=\frac{3}{2}$

=>  d = 1, 99

=> d = 99 satisfies.

Therefore, Distance between A and B = 99