Time and Distance Questions

FACTS  AND  FORMULAE  FOR  TIME  AND  DISTANCE

1.Speed = DistanceTime,  Time=DistanceSpeed, Distance= Speed×Time 

 

2. x km/hr = x×518 m/sec

 

3. x m/sec = x×185 km/hr

4. If the ratio of the speeds of A and B is a:b , then the ratio of the times taken by them to cover the same distance is or b : a

5. Suppose a man covers a certain distance at x km/ hr and an equal distance at y km/hr . Then, the average speed during the whole journey is 2xyx+ykm/hr.

Q:

A person crosses a 600 m long street in 5 minutes, What is his speed in km per hour?

A) 3.6 B) 7.2
C) 8.4 D) 10
 
Answer & Explanation Answer: B) 7.2

Explanation:

Speed =   6005×60 m/sec= 2 m/sec = 2 x (18/5) km/hr = 7.2 km/hr

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Q:

The speed of a car increases by 2 kms after every one hour. If the distance travelling in the first one hour was 35 kms. what was the total distance travelled in 12 hours?

A) 456 kms B) 482 kms
C) 552 kms D) 556 kms
 
Answer & Explanation Answer: C) 552 kms

Explanation:

Total distance travelled in 12 hours    =(35+37+39+.....upto 12 terms)
This is an A.P with first term, a=35, number of terms,
n= 12,d=2.
Required distance    = 12/2[2 x 35+{12-1) x 2]
=6(70+23)
= 552 kms.

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327 58643
Q:

A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?

A) 100 m B) 150 m
C) 190 m D) 200 m
 
Answer & Explanation Answer: A) 100 m

Explanation:

Relative speed of the thief and policeman  =  (11 – 10) km/hr = 1 km/hr 

Distance covered in 6 minutes  = (1/60) x 6 km   = 1/10 km = 100 m

Therefore, Distance between the thief and policeman = (200 – 100) m = 100 m.

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226 56627
Q:

A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is

A) 35.55 km/hr B) 36 km/hr
C) 71.11 km/hr D) 71 km/hr
 
Answer & Explanation Answer: C) 71.11 km/hr

Explanation:

Total time taken    = (160/64 + 160/8)hrs
                           = 9/2 hrs.


Average speed    = (320 x 2/9) km.hr
                         = 71.11 km/hr.

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143 52543
Q:

Two trains A and B start simultaneously in the opposite direction from two points P and Q and arrive at their destinations 16 and 9 hours respectively after their meeting each other. At what speed does the second train B travel if the first train travels at 120 km/h

A) 90 km/h B) 160 km/h
C) 67.5 km/h D) None of these
 
Answer & Explanation Answer: B) 160 km/h

Explanation:

s1s2=t2t1

120s2=916=34

s2=160km/h

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149 38546
Q:

How long will a boy take to run round a square field of side 35 meters, If he runs at the rate of 9 km/hr?

A) 50 sec B) 52 sec
C) 54 sec D) 56 sec
 
Answer & Explanation Answer: D) 56 sec

Explanation:

Speed = 9 km/hr = 9 x (5/18) m/sec = 5/2 m/sec   

Distance = (35 x 4) m = 140 m.

Time taken = 140 x (2/5) sec= 56 sec

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120 33864
Q:

The ratio between the speeds of two trains is 7: 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is ?

A) 83.5 km/hr B) 84.5 km/hr
C) 86.5 km/hr D) 87.5 km/hr
 
Answer & Explanation Answer: D) 87.5 km/hr

Explanation:

Let the speeds of two trains be 7X and 8X km/hr.

8x = 400/4

=> x= 12.5 km/hrX=4004=>X=12.5Km/hr

So speed of first train is 12.5*7 = 87.5 km/hr

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60 32427
Q:

Two horses start trotting towards each other, one from A to B and another from B to A. They cross each other after one hour and the first horse reaches B, 5/6 hour before the second horse reaches A. If the distance between A and B is 50 km. what is the speed of the slower horse?

A) 30 km/h B) 15 km/h
C) 25 km/h D) 20 km/h
 
Answer & Explanation Answer: D) 20 km/h

Explanation:

If the speed of the faster horse be fs and that of slower horse be ss then

 fs+ss=501=50 

and       50ss-50fs=56

Now, you can go through options.

The speed of slower  horse is 20km/h

Since,   20+30=50

and  5020-5030=56    

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