A) 5:3 | B) 1:4 |

C) 4:1 | D) 9:1 |

Explanation:

Milk = 3/5 x 20 = 12 liters, water = 8 liters

If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.

Remaining milk = 12 - 6 = 6 liters

Remaining water = 8 - 4 = 4 liters

10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.

The ratio of milk and water in the new mixture = 16:4 = 4:1

If the process is repeated one more time and 10 liters of the mixture are removed,

then amount of milk removed = 4/5 x 10 = 8 liters.

Amount of water removed = 2 liters.

Remaining milk = (16 - 8) = 8 liters.

Remaining water = (4 -2) = 2 liters.

Now 10 lts milk is added => total milk = 18 lts

The required ratio of milk and water in the final mixture obtained

= (8 + 10):2 = 18:2 = 9:1.

A) 10 : 9 | B) 8 : 7 |

C) 9 : 8 | D) 5 : 4 |

A) 45% | B) 33 1/3% |

C) 25 % | D) 12 1/2% |

A) 289 : 54 | B) 9 : 6 |

C) 17 : 17 | D) 2 : 3 |

A) 7 : 4 | B) 2 : 1 |

C) 5 : 2 | D) 8 : 3 |

A) 4 : 7 | B) 3 : 5 |

C) 2 : 3 | D) 1 : 2 |

A) 21 : 16 : 7 | B) 17 : 21 : 4 |

C) 63 : 48 : 14 | D) 68 : 28 : 21 |

A) 26 : 25 | B) 51 : 32 |

C) 46 : 45 | D) 34 : 25 |

A) 11:13 | B) 13:11 |

C) 9:11 | D) 11:9 |