Quantitative Aptitude - Arithmetic Ability Questions

Q:

7 9 19 18 31 29

Find the odd number in the given Number Series?

A) 31 B) 29
C) 18 D) 19
 
Answer & Explanation Answer: B) 29

Explanation:

Here the given number series follows a pattern of two alternate series.

1. 7 19 31 ...(Difference of 12)

2. 9 18 27 ...(Difference of 9)

Here the odd number is 29 instead of 27

And the next number is 31 + 12 = 43 & 27 + 9 = 36

 

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13 115074
Q:

Find the next number in te given series ?

5, 25, 61, 113, ...

A) 142 B) 181
C) 156 D) 179
 
Answer & Explanation Answer: B) 181

Explanation:

Here the series follow the rule that

12+22 = 5

32+42 = 25

52+62 = 61

72+82 = 113

 

SO NEXT IS, 92+102 = 181

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14 115013
Q:

What will come in place of the question mark (?) in the following number series?

5, 7, ?, 25, 45, 75

A) 11 B) 13
C) 15 D) 19
 
Answer & Explanation Answer: B) 13

Explanation:

The series given follow the pattern

 

+2, +2+4, +2+4+6, +2+4+6+8, +2+4+6+8+10,...

 

Here ? = 7 + 2 + 4 = 13.

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10 114729
Q:

ΔXYZ is right angled at Y. If sinX = 12/13, then what is the value of cosecZ ?

 

A) 5/12   B)  5/13  
C) 13/5   D)  13/12
 
Answer & Explanation Answer: C) 13/5  

Explanation:
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2 114036
Q:

What will come in place of question mark (?) in the following number series?

4, 3, 4, 7, 15, ?

A) 42 B) 44
C) 53 D) 56
 
Answer & Explanation Answer: B) 44

Explanation:

  4             3             4             7               15        ?
×1-1      ×1+1       ×2-1       ×2+1           ×3-1

 

15x3 - 1 = 45 - 1 = 44

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8 113748
Q:

SM@A#N2B4O&3C5P+D2

Using the above sequence find the characters that do NOT belong the group?

AO+, MB5, N32, $2P

 

A) N32 B) AO+
C) $2P D) MB5
 
Answer & Explanation Answer: C) $2P

Explanation:
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0 112998
Q:

What should come in place of question mark (?) in the following question?

52000 ÷ 40 ÷ 65 × 30 = ? - √400

A) 580 B) 620
C) 720 D) 780
 
Answer & Explanation Answer: B) 620

Explanation:

52000 ÷ 40 ÷ 65 × 30 = ? - √400

(52000 ÷ 40) ÷ 65 × 30 = ? - 20

(1300 ÷ 65) × 30 = ? - 20

20 × 30 = ? - 20

600 = ? - 20

? = 620

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Q:

A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:

A) 2/91 B) 1/22
C) 3/22 D) 2/77
 
Answer & Explanation Answer: A) 2/91

Explanation:

Let S be the sample space.

Then, n(S) = number of ways of drawing 3 balls out of 15 = 15C3  =15*14*133*2*1= 455.  

Let E = event of getting all the 3 red balls.

 n(E) = 5C3 = 5*42*1 = 10.

 => P(E) = n(E)/n(S) = 10/455 = 2/91.

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