Quantitative Aptitude - Arithmetic Ability Questions

Q:

The population of a town was 3600 three years back. It is 4800 right now. What will be the population three years down the line, if the rate of growth of population has been constant over the years and has been compounding annually?

A) Rs.600 B) Rs,6400
C) Rs.6500 D) Rs.6600
 
Answer & Explanation Answer: B) Rs,6400

Explanation:

 

The population grew from 3600 to 4800 in 3 years. That is a growth of 1200 on 3600 during three year span.

 

Therefore, the rate of growth for three years has been constant.

 

The rate of growth during the next three years will also be the same.

 

Therefore, the population will grow from 4800 by 4800*13= 1600

 

Hence, the population three years from now will be 4800 + 1600 = 6400

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

30 26218
Q:

Three solid cubes of sides 1 cm, 6 cm and 8 cm are melted to form a new cube. Find the surface area of the cube so formed

A) 486 B) 586
C) 686 D) 786
 
Answer & Explanation Answer: A) 486

Explanation:

Volume of new cube =  13+63+83cm3729cm3  

Edge of new cube = 7293 = 9cm

Surface area of the new cube = ( 6 x 9 x 9) sq.cm = 486 sq.cm

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41 26177
Q:

What will Rs.1500 amount to in three years if it is invested in 20% p.a. compound interest, interest being compounded annually?

A) Rs.2592 B) Rs.2492
C) Rs.2352 D) Rs.2352
 
Answer & Explanation Answer: A) Rs.2592

Explanation:

The usual way to find the compound interest is given by the formula A = .p(1+r/100)^n

In this formula,

A is the amount at the end of the period of investment

P is the principal that is invested

r is the rate of interest in % p.a

And n is the number of years for which the principal has been invested.

In this case, it would turn out to be A =1500(1+20/100)^3

= 2592.

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

9 26126
Q:

In how many ways a committee, consisting of 5 men and 6 women can be formed from 8 men and 10 women?

A) 53400 B) 17610
C) 11760 D) 45000
 
Answer & Explanation Answer: C) 11760

Explanation:

Required number of ways = 8C5*10C6 =  8C3*10C4 = 11760

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25 26104
Q:

Without any stoppage, a person travels a certain distance at an average speed of 42 km/h, and with stoppages he covers the same distance at an average speed of 28 km/h. How many minutes per hour does he stop?

A) 15 minutes B) 20 minutes
C) 18 minutes D) 22 minutes
 
Answer & Explanation Answer: B) 20 minutes

Explanation:

Let the total distance to be covered is 84 kms.
Time taken to cover the distance without stoppage = 84/42 hrs = 2 hrs
Time taken to cover the distance with stoppage = 84/28 = 3 hrs.
Thus, he takes 60 minutes to cover the same distance with stoppage.
Therefore, in 1 hour he stops for 20 minutes.

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Filed Under: Average
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO

27 26099
Q:

A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and 24% of 50 p coins are removed, the percentage of money removed from the bag is nearly :

A) 21.6 % B) 15.3 %
C) 14.6 % D) 12.5 %
 
Answer & Explanation Answer: A) 21.6 %

Explanation:

Total money = Rs.[600*(25/100)+1200*(50/100)]= Rs. 750.

 

25 paise coins removed = Rs. (600*12/100) = 72.

 

50 paise coins removed = Rs. (1200*24/100)= 288.

 

Money removed =Rs.(72*25/100+288*50/100)  = Rs.162.

 

Required percentage = (162/750*100)% = 21.6 %.

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Filed Under: Percentage

57 26099
Q:

The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence.

Answer

Given that, A+B = 60  and A = 2B.


Solving, We get A = 40, B = 20.


Five years their ages will be 45 and 25, so the sum of their ages will be 70.


 

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Subject: Problems on Ages

71 25987
Q:

The mean temperature of Monday to Wednesday was 37C and of Tuesday to Thursday was 34C . If the temperature on Thursday was (4/5) th that of Monday, the temperature on Thursday was?

Answer

\inline \fn_jvn M+T+W =(37\times 3)^{0}=111^{0}C   -----------(1)


\inline \fn_jvn T+W+Th=(34\times 3)^{0}=102^{0}C


\inline \fn_jvn \Rightarrow T+W+\frac{4}{5}M = 102^{0}C                --------------(2)


(1) - (2) gives


\inline \fn_jvn \frac{1}{5} th of temperature on Monday = 


\inline \fn_jvn \Rightarrow Temperature on Monday = \inline \fn_jvn 45^{0}C


\inline \fn_jvn \therefore Temperature on Thursday = \inline \fn_jvn \frac{4}{5}\times 45^{0}=36^{0}

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Subject: Average

160 25978