Quantitative Aptitude - Arithmetic Ability Questions

Sum =(B.D. x T.D.)/(B.D. - T.D.)

       = Rs. (72 x 60) / (72 - 60)

       = Rs. (72 x 60) /12

       = Rs. 360.

I = PTR/100
I = 25 x 4 x 0.03/100
I = 0.03 x 100 = 300 Ps = Rs. 3

On dividing we get

75)8485(113
     75
     ------
       98
       75
      ------
       235
       225
      ------
         10
      ------
Required number = (8485-10)=8475.

Let Kumar’s present age be "x" years and Sailesh’s present age be "y" years.
Then, according to the first condition,

x - 10 = 3(y - 10) => x - 3y = - 20 ........(1)

Now, Kumar’s age after 10 years = (x + 10) years.

Sailesh’s age after 10 years = (y + 10) years.

(x + 10) = 2 (y + 10)  => x - 2y = 10 ......(2)

Solving (1) and (2),

we get x = 70 and y = 30

Kumar’s present age = 70 years    and  Sailesh’s present age = 30 years.

Let the distance and original speed be 'd' km and 'k' kmph respectively.

d/0.8k - d/k = 20/60 => 5d/4k - d/k = 1/3

=> (5d - 4d)/4k = 1/3 => d = 4/3 k

Time taken to cover the distance at original speed

= d/k = 4/3 hours = 1 hour 20 minutes.

Here clock-wise and anti-clockwise arrangements are same.

Hence total number of circular–permutations: 18P122*12 = 18!6*24

|-----------20--------------------|
50                           40

Difference = 20kms

Relative Speed = 50 – 40 = 10 kmph

Time = 20/10 = 2 hours.

F = Rs. 2160

TD = Rs. 360

PW = F - TD = 2160 - 360 = Rs. 1800

True Discount is the Simple Interest on the present value for unexpired time

=>Simple Interest on Rs. 1800 for unexpired time = Rs. 360

Banker's Discount is the Simple Interest on the face value of the bill for unexpired time

= Simple Interest on Rs. 2160 for unexpired time

=(360/1800)* 2160

= (1/5) * 2160

=Rs. 432