Quantitative Aptitude - Arithmetic Ability Questions

P.W = [100 x Amount] / [100+(R x T)]

=[100 x 930] / [100+(8x3)] = Rs. 750 

T.D = Amount - P.W = 930 - 750 = Rs.180

Length of the wire fencing = perimeter = 2(90 + 50) = 280 metres

Two poles will be kept 5 metres apart. Also remember that the poles will be placed along the perimeter of the rectangular plot, not in a single straight line which is very important.

Hence number of poles required = 280 / 5 = 56

Let, Ages of Vijaya and Simran – 1 year ago was 4A and A years correspondingly.
Then, [(4A + 1) + 6] – [(A + 1) + 6] = 9
3A = 9  => A = 3

Needed Ratio = (4A + 1) : (A + 1) = 13 : 4

Total Items = 7
Discounted = 1
Percentage = 1/7 x 100
= 14.285%

1 hectare = 10,000 Sq.m

So, Area = (1.5 x 10000) Sq.m

Depth = 5/100 m = 1/20 m

Therefore, Volume = Area X Depth = 15000 x (1/20)= 750 cu.m

Except Granite all other options belong to the group of precious stones.

Ratio of shares of A,B,C = (24 x 4) : (10 x 6) : (56 x 5)

                                    = 96 : 60 : 280.

Let total rent be Rs. x. Then, A's share = Rs.96x436

 ∴96x436=960 ⇔x=960×43696=4360

Hence total rent of the field is Rs. 4360.

We know that Time is inversely proportional to Efficiency

Here given time ratio of P & P+Q as

P/P+Q = 150/100 = 3:2

Efficiency ratio of P & Q as

P:Q = 2:1 ....(1)

Given Efficiency ratio of Q & R as

Q:R = 3:1 ....(2)

From (1) & (2), we get

P:Q:R = 6:3:1

P alone can finish the work in

22.5(3+1)/6 = 15 days.