6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A, B and C can do a piece of work in 72, 48 and 36 days respectively. For first p/2 days, A & B work together and for next ((p+6))/3days all three worked together. Remaining 125/3% of work is completed by D in 10 days. If C & D worked together for p day then, what portion of work will be remained?

A) 1/5	B) 1/6
C) 1/7	D) 1/8

Answer & Explanation Answer: B) 1/6

Explanation:

Total work is given by L.C.M of 72, 48, 36

Total work = 144 units

Efficieny of A = 144/72 = 2 units/day

Efficieny of B = 144/48 = 3 units/day

Efficieny of C = 144/36 = 4 units/day

According to the given data,

2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100

3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54

p = 198/16.5

p = 12 days.

Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day

(C+D) in p days = (4 + 6) x 12 = 120 unit

Remained part of work = (144-120)/144 = 1/6.

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Filed Under: Time and Work
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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7 8454

Q:

K and L starts walking towards each other at 4 pm at speed of 3 km/hr and 4 km/hr respectively. They were initially 17.5 km apart. At what time do they meet ?

A) 6:00 am	B) 6:30 pm
C) 5:45 am	D) 5:52 pm

Answer & Explanation Answer: B) 6:30 pm

Explanation:

Suppose they meet after 'h' hours

Then

3h + 4h = 17.5

7h = 17.5

h = 2.5 hours

So they meet at => 4 + 2.5 = 6:30 pm

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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12 8452

Q:

On a ruler's tombstone, it is said that one sixth of his life was spent in childhood and one twelfth as a teenager. One seventh of his life passed between the time he became an adult and the time he married; five years later, his son was born. Alas, the son died four years before he did. He lived to be twice as old as his son did. How old did the ruler live to be ?

A) 84 years	B) 72 years
C) 82 years	D) 64 years

Answer & Explanation Answer: A) 84 years

Explanation:

Let the age of ruler is x so that of son = x/2 (given)
Now according to the given condition
(x/6) + (x/12) + (x/7) + 5 + (x/2) + 4 = x
=> x = 84

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Filed Under: Problems on Ages
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6 8452

Q:

From a container of wine, a thief has stolen 15 litres of wine and replaced it with same quantity of water. He again repeated the same process. Thus, in three attempts the ratio of wine and water became 343 : 169. The initial amount of wine in the container was:

A) 75 litres	B) 100 litres
C) 150 litres	D) 120 litres

Answer & Explanation Answer: D) 120 litres

Explanation:

$\frac{w i n e (l e f t)}{w i n e (a d d e d)} = \frac{343}{169}$

It means $\frac{w i n e (l e f t)}{w i n e (i n i t i a l a m o u n t)} = \frac{343}{512}$ (since 343 + 169 = 512)

Thus, $343 x = 512 x {(1 - \frac{15}{k})}^{3}$

$\frac{343}{512} = {(\frac{7}{8})}^{3} = {(1 - \frac{15}{k})}^{3}$

$(1 - \frac{15}{k}) = \frac{7}{8} = (1 - \frac{1}{8})$

Thus the initial amount of wine was 120 liters.

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Filed Under: Alligation or Mixture
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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29 8449

Q:

In what time will Rs.1000 become Rs.1331 at 10% per annum compounded annually?

A) 2years	B) 3years
C) 4years	D) 5years

Answer & Explanation Answer: B) 3years

Explanation:

Principal = Rs.1000;

Amount = Rs.1331;

Rate = Rs.10%p.a.

Let the time be n years.Then

[1000(1+10/100)Λn;]

= 1331.

= (1331/1000)

= (11/10)³

Therefore n = 3 years.

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

3 8449

Q:

For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 200?

A) 48	B) 49
C) 50	D) 51

Answer & Explanation Answer: C) 50

Explanation:

1 < 4n + 7 < 200

n can be 0, or -1

n cannot be -2 or any other negative integer or the expression 4n + 7 will be less than1.

The largest value for n will be an integer < (200 - 7) /4

193/4 = 48.25, hence 48

The number of integers between -1 and 48 inclusive is 50

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Filed Under: Numbers
Exam Prep: GRE

2 8446

Q:

The bankers discount and the true discount of a sum at 10% per annum simple interest for the same time are Rs.100 and Rs.80 respectively. What is the sum and the time?

A) Sum = Rs.400 and Time = 5 years	B) Sum = Rs.200 and Time = 2.5 years
C) Sum = Rs.400 and Time = 2.5 years	D) Sum = Rs.200 and Time = 5 years

Answer & Explanation Answer: C) Sum = Rs.400 and Time = 2.5 years

Explanation:

BD = Rs.100

TD = Rs.80

R = 10%

$F = \frac{B D \times T D}{B D - T D} = \frac{100 \times 80}{100 - 80} = R s . 400$

BD = Simple interest on the face value of the bill for unexpired time= FTR/100

$\Rightarrow 100 = \frac{400 \times T \times 10}{100}$

=> T = 2.5 years

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Filed Under: Banker's Discount

4 8445

Q:

A and B together finish a wor in 20 days.They worked together for 15 days and then B left. Afer another 10 days,A finished the remaining work. In how many days A alone can finish the job?

A) 30	B) 40
C) 50	D) 60

Answer & Explanation Answer: B) 40

Explanation:

(A+B)'s 15 days work = $(\frac{1}{20} \times 15) = \frac{3}{4}$

Remaining work = 1/4

Now, 1/4 work is done by A in 10 days.

Whole work will be done by A in (10 x 4) = 40 days.

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Filed Under: Time and Work

9 8444

Quantitative Aptitude - Arithmetic Ability Questions

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