6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In a mixture of 240 lt. water is 20% and rest is Milk. What quantity of mixture should be taken out and replaced with water so that water becomes 40%?

A) 60 lit	B) 55 lit
C) 45 lit	D) 50 lit

Answer & Explanation Answer: A) 60 lit

Explanation:

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Filed Under: Alligation or Mixture
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15 7266

Q:

What is the difference between the biggest and the smallest fraction among 2/3 , 3/4 , 4/5 and 5/6?

A) 1/6	B) 1/12
C) 1/20	D) 1/30

Answer & Explanation Answer: A) 1/6

Explanation:

Converting each of the given fractions into decimal form, we get

2/3 = 0.66, 3/4 = 0.75, 4/5 = 0.8, 5/6 = 0.833

Since 0.833>0.8>0.75>0.66

So, 5/6 > 4/5 > 3/4 > 2/3

Therefore, Required Difference = 5/6 - 2/3 = 1/6

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Filed Under: Decimal Fractions

5 7264

Q:

7 years ago, the ratio of the ages of Anirudh to that of Bhavana, was 7:9. Chandhu is 12 years older than Anirudh and 12 years younger than Bhavana. What is Chandhu's present age?

A) 91 years	B) 115 years
C) 103 years	D) Can't be determined

Answer & Explanation Answer: C) 103 years

Explanation:

Let present Anirudh's age be 'A' and Bhavana's age be 'B'

Given seven years, their ratio is 7:9

=> A-7 : B-7 = 7 : 9

=> 9A - 7B = 14 .......(1)

And given,

Chandhu is 12 years older than A nad 12 years younger than B

=> C = A + 12....(2)

=> B = C + 12

=> B = A + 12 + 12 .....(From (2))

=> B = A + 24 ....(3)

Put (3) in (1)

9A - 7(A+24) = 14

9A - 7A - 168 = 14

2A = 182

=> A = 91 years

=> C = A + 12 = 91 +12 = 103 years.

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Filed Under: Problems on Ages
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9 7263

Q:

Two trains start from same place at same time at right angles to each other. Their speeds are 36km/hr and 48km/hr respectively. After 30 seconds the distance between them will be ?

A) 900 mts	B) 300 mts
C) 250 mts	D) 500 mts

Answer & Explanation Answer: D) 500 mts

Explanation:

Using pythagarous theorem,
distance travelled by first train = 36x5/18x30 = 300m
distance travelled by second train = 48x5/18x30 = 400m
so distance between them =√( 90000 + 160000) = √250000 = 500mts.

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Filed Under: Time and Distance
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8 7259

Q:

A duster is of dimension 5x5x7 all in cms, is sinked into a cylindrical vessel of radius 5 cm and height 10 cm. After insertion the level of the water is inccresed by 2.14 cm. Then by what percentage the part of the duster is above the layer ?

A) 96 %	B) 4 %
C) 97 %	D) 3 %

Answer & Explanation Answer: B) 4 %

Explanation:

Imension of the duster is assumed as 5x5x7 cm3

Volume of the duster below the water layer
= volume of water increased
= πxrxrxh = 3.14×52×2.14 ≈ 168 cm3

Total volume of the duster = 5×5×7 = 175 cm3

Percentage of the duster part below the layer = 168×100/175 = 96%

Percentage of the duster part above the layer = 4%

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Filed Under: Percentage
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4 7245

Q:

A sold an article to B at 40% profit and B sold it to C at 50% profit, then what will be profit percent with respect to A ?

A) 97 %	B) 110 %
C) 135 %	D) 115 %

Answer & Explanation Answer: B) 110 %

Explanation:

% Profit with respect to A = 40 + 50 + (40 x 50)/100 = 90 + 20 = 110 %.

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Filed Under: Profit and Loss
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2 7242

Q:

(10.3 * 10.3 * 10.3 + 1)/(10.3 * 10.3 - 10.3 + 1) is :

A) 11.3	B) 12.3
C) 13.3	D) 14.3

Answer & Explanation Answer: A) 11.3

Explanation:

a^3 + b^3 = (a+ b) * (a^2 + b^2 - ab)

[ (10.3)^3 + (1)^3 ] / [(10.3)^2 + (1)^2 - (1 * 10.3)]

=> a + b = 10.3 + 1 = 11.3

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Filed Under: Decimal Fractions

6 7240

Q:

The Value of $[\log (\tan (1^{0})) + \log (\tan (2^{0})) + \dots \dots + \log (\tan (89^{0}))]$ is

A) -1	B) 0
C) 1/2	D) 1

Answer & Explanation Answer: B) 0

Explanation:

$= [\log \tan (1^{0}) + \log \tan (89^{0})] + [\log \tan (2^{0}) + \log \tan (88^{0})] + \dots \dots + [\log \tan (45^{0})]$

$= \log [\tan (1^{0}) \times \tan (89^{0})] + \log [\tan (2^{0}) \times \tan (88^{0})] + \dots \dots + \log (1)$

$[∵ \tan (90 - θ) = c o t θ a n d \tan (45^{0}) = 1]$

= log 1 + log 1 +.....+log 1

= 0.

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Filed Under: Logarithms
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27 7234

Quantitative Aptitude - Arithmetic Ability Questions

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