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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

The payment per hour for a daily-wages employee is increased by 33.33 and the working time is reduced by 33.33%. What is the percentage change in the employee's income ?

A) 11.11% decrease B) 21.11% increase
C) 11.11% increase D) 21.11% decrease
 
Answer & Explanation Answer: A) 11.11% decrease

Explanation:

If earlier he is getting Rs. 1  per hr and working for 1 hr, income = Rs. 1
Now he is getting Rs 1.3333 per hr and working for 0.66667 hrs

Then income for 0.66667 hrs = Rs. 0.8889.

If payment per hr is increased by 33.33 %  and working hours dereased by 33.33%, then 11.11 % decrease in income.

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Filed Under: Percentage
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Q:

The question given below contain two statements giving certain data. You have to decide whether the data given in the statements are sufficient for answering the question ?

Question :

What is the height of a right-angled triangle ?

Statements :

A. The area of the triangle is 20 times its base.

B. The perimeter of the triangle is equal to that of a square of the side 10 cm.

A) Only statement A is required B) Only statement B is required
C) Both A & B are required D) Neither (A) nor (B) is reuired
 
Answer & Explanation Answer: A) Only statement A is required

Explanation:

From statement (A),

20b = (1/2) × b × h

h = 40 cm.

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Filed Under: Area
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27 6430
Q:

Calculate the number of bricks, each measuring 25 cm x 15 cm x 8 cm required to construct a wall of dimensions 10 m x 4 m x 5 m when 10% of its volume is occupied by concrete ?

A) 6000 B) 5400
C) 3800 D) 4700
 
Answer & Explanation Answer: A) 6000

Explanation:

Let 'B' be the nuber of bricks.

=> 10 x 4/100 x 5 x 90/100 = 25/100 x 15/100 x 8/100 x B

=> 10 x 20 x 90 = 15 x 2 x B

=> B = 6000

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Filed Under: Volume and Surface Area
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5 6428
Q:

Sushma joins a job at 20 yrs. First 3 years salary is 10,000 p.a. Afterwards every year increment of 2,000 per year for 10 years. Then salary becomes constant till retirement. At retirement average salary is 25,000. (throughout career). At what age Sushma retires ?

A) 50 yrs B) 47 yrs
C) 45 yrs D) 42 yrs
 
Answer & Explanation Answer: A) 50 yrs

Explanation:

Let age of retirement = S
so according to the given condition 25000(x-20)
=10000 x 3 + 12000 + 14000 + 16000 + 18000 + 20000 + 22000 + 24000 + 26000 + 28000 + 30000 + 30000(S-33)
= 30000 + 210000 + 30000S-990000
= 30000S - 750000
or 25000S - 500000 = 30000x - 750000
or 5000x = 250000
or S = 50 yrs.

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Filed Under: Problems on Ages
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4 6426
Q:

Find the range and mode of the data 17, 18, 28, 19, 16, 18, 17, 29, 18

A) 12 and 18 B) 13 and 18
C) 12 and 17 D) 11 and 17
 
Answer & Explanation Answer: B) 13 and 18

Explanation:
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Filed Under: Probability
Exam Prep: Bank Exams

41 6403
Q:

The number of signals that can be generated by using 5 differently coloured flags, when any number of them may be hoisted at a time is:

A) 235 B) 253
C) 325 D) None of these
 
Answer & Explanation Answer: C) 325

Explanation:

Required number of signals = 5P1 + 5P2 + 5P3 + 5P4 + 5P5

= 5 + 20 + 60 + 120 + 120 = 325

 

 

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Filed Under: Permutations and Combinations
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4 6396
Q:

Ravi, Anand and Pranay are running a business firm in partnership. What is Anand's share in the profit earned by them?

a. Ravi, Anand and Pranay invested the amounts in the ratio of 2 : 4 : 7.

b. Pranay's share in the profit is Rs. 8750.

A) Only a is sufficient B) Neither a nor b is sufficient
C) Only b is sufficient D) Both a and b sufficient
 
Answer & Explanation Answer: D) Both a and b sufficient

Explanation:

Given Pranay's profit in the share is Rs. 8750

But given that their investments are in the ratio 2:4:7

713×P = 8750

P = 16250


Now Anand's share = 413×16250 = Rs.5000

Thus both staements a and b are sufficient to answer this question.

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Filed Under: Partnership
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3 6394
Q:

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A) 25% increase B) 50% increase
C) 50% decrease D) 75% decrease
 
Answer & Explanation Answer: B) 50% increase

Explanation:

Let original length = x and original breadth = y.

Original area = xy.

 

New length = x/2 and New breadth = 3y.

New area = (x/2 * 3y) = (3/2 )xy

 

Therefore,  Increase % = [(1/2)xy * (1/xy) * 100] % = 50%

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Filed Under: Volume and Surface Area

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