Quantitative Aptitude - Arithmetic Ability Questions

Let the three parts M, N, O.
Then, M:N = 2:3 and N:O = 5:8
= (5 x 3/5) : (8 x 3/5) = 3:24/5

M:N:O = 2:3:24/5

= 10:15:24 => N = 98 x 15/49 = 30.

Given height of the conical tent = 3 m

Diameter = 10 => Radius = D/2 = 10/2 = 5 m 

Now, as the tent is in the conical form

Volume of the conical tent = πr2h3 

=> (22 x 5 x 5 x 3) / (7 x 3) 

= 22 x 25/7 

= 78.54 cu.m 

Given each person requires 3.92 cu.m of air 

=> Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20

Let original length = x and original breadth = y. 

Decrease in area = xy -[(80/100x) * (90/100y)]  

=[(xy-(18/25)xy)]

=(7/25)xy

Decrease % =[(7/25)xy * (1/xy) * 100] =28%

As we know that Speed = Distance / Time
for average speed = Total Distance / Total Time Taken
Thus, Total Distance = 325 + 470 = 795 km
Thus, Total Speed = 7.5 hrs
Average Speed = 795/7.5 => 106 kmph.

Total number of cases=36

Number of favourable cases(sum 5 or 6)=10

P(getting total of 5 or 6)=10/36=5/18

1. To find the interest, subtract the principal from the balance.

       $618 - $600 = $18

2.Use the simple interest formula and solve for r.

       I = Prt

      18= 600 x r x (1/2)

       r= 0.06 =6%

Using Trial and error method,

we get the number of girls in the hall = 78

Let amount be Rs.x then,  

 [X * R * T] / [100 + (R * T)] = T.D  

=> [x * 12 * (3/4)] / [100+(12 * 3/4)] =540  

=> x = 6540  

Amount = Rs.6540   

P.W = Rs.(6540 -540) = Rs.6000