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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

Find the area of the trapezium, whose parallel sides are 12 cm and 10 cm, and distance between the parallel sides is 14 cm?

A) 121 sq.com B) 154 sq.com
C) 186 sq.com D) 164 sq.com
 
Answer & Explanation Answer: B) 154 sq.com

Explanation:

We know that, 

Area of trapezium = 1/2 x (Sum of parallel sides) x (Distance between Parallel sides)

= 1/2 x (12 + 10) x 14

= 22 x 14/2

= 22 x 7

= 154 sq. cm

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Filed Under: Area
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Q:

The ratio of present ages of Simi and Seema is 5 : 4. After 9 years the ratio of their ages will be 8 : 7. What is Simi's present age (in years)?

A) 12 B) 15
C) 24 D) 21
 
Answer & Explanation Answer: B) 15

Explanation:
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Filed Under: Problems on Ages
Exam Prep: Bank Exams

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Q:

[15% of 300% of 560] × 2 ÷ 5 =

A) 100 B) 90
C) 85 D) 105
 
Answer & Explanation Answer: A) 100

Explanation:

[15% of 300% of 560] × 2 ÷ 5

= (15 x 300 x 560 x 2)/100 x 100 x 5

~= 100 

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Filed Under: Simplification
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Q:

What is a Common Multiple?

Answer

If the Multiples for two or more numbers which are Common, then those Multiples are said to be Common Multiples. 


 


For Example :


Multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30,...


Multiples of 5 are 5, 10, 15, 20, 25, 30,...


Here common multiples of 3 & 5 upto 30 are 15, 30.

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Subject: HCF and LCM Exam Prep: AIEEE , Bank Exams , CAT , GATE
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Q:

Radha and Hema are neighbours and study in the same school. Both of them use bicycles to go to the school. Radha’s speed is 8 km/hr whereas Hema’s speed is 10 km/hr. Hema takes 9 minutes less than Radha to reach the school. How far is the school from the locality of Radha and Hema?

A) 5 km B)  5.5 km
C) 6 km D) 6.5 km
 
Answer & Explanation Answer: C) 6 km

Explanation:
Let the distance between be D km
Time taken by radha – Time taken by Hema = 9 mins
So D/8 – D/10 = 9/60 hrs
D = 6km
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Filed Under: Time and Distance
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Q:

A cube is inscribed in a sphere. A right circular cylinder is within the cube touching all the vertical faces. A right circular once is inside the cylinder. Their heights are same and the diameter of the cone is equal to that of the cylinder.

What is the ratio of the volume of the sphere to that of cone?

A) 6√3:1 B) 7 : 2
C) 3√3:1   D) 5√3:1
 
Answer & Explanation Answer: A) 6√3:1

Explanation:
The top view of the given assembly will look like the figure above
Outermost is the sphere. Inside that there is a cube and within that there is a cone and cylinder with same radius.
Here side of cube = a
Diameter of Sphere = body diagnol = √3 a
Radius of sphere = √3 a/2 =r1
Height of Cylinder = Height of cone = side of cube = a =h
Radius of cylinder = Radius of cone = side of cube/2 = a/2 =r2(as shown in the figure)
Volume of sphere/volume of cone = 43πr1313πr22h = 6√3:1
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Filed Under: Volume and Surface Area
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Q:

For a nominal interest rate of 8.4%, what is the compounding frequency if the periodic interest rate is:2.1

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: D) 4

Explanation:

i=j/m

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Filed Under: Compound Interest
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Q:

What least number must be substracted from 627349 so that the remaining number is divisible by 15 ?

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: D) 4

Explanation:

On dividing 627349 by 15, we get remainder = 4.
Therefore, the obtained remainder is the least number to be subtracted from the given number so that the the mnumber is divisible by 15.
Here 4 is the least number to be subtracted from 627349 so that it is divisible by 15.

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Filed Under: Numbers
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