Quantitative Aptitude - Arithmetic Ability Questions

Originally let there be x men.

Less men, More days     (Indirect Proportion)

 Therefore, (x-10) : x  :: 100 :110

=> (x - 10) * 110 = x * 100    => x= 110

A : B : C = 500 : 300 : 200 = 5 : 3 : 2.

Let their capitals be 5x, 3x and 2x respectively.

Then, 5x = 10000  

=>  x = 2000.

C's capital = 2x = Rs. 4000.

For 1st year S.I =C.I.

Thus, Rs.16 is the S.I. on S.I. for 1 year, which at 8% is thus Rs.200

i.e S.I on the principal for 1 year is Rs.200

Principle = Rs.100*2008*1 = Rs.2500

Amount for 2 years, compounded half-yearly

 Rs.2500*1+41004=Rs.2924.4

C.I = Rs.424.64

Also, S.I=Rs.2500*8*2100=Rs.400

Hence, [(C.I) - (S.I)] = Rs. (424.64 - 400) = Rs.24.64

The only even numbers in the list are 2 and 4, but 4 is not a prime. So 2 can be used to illustrate the statement that all primes are not odd.

The given series is 1/2, 1, 3/2, 6, 5/2, 3

1/2

1/2 + 1/2 = 1

1 + 1/2 = 3/2

3/2 + 1/2 = 2 (Not 6)

2 + 1/2 = 5/2

5/2 + 1/2 = 3

Hence, the odd man in the given number series is 6.

Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.

R=100*60100*6 =10% p.a

Now, P = Rs. 12000. T = 3 years and R = 10% p.a.

C.I=Rs.12000*1+101003-1
       =Rs.3972