FACTS  AND  FORMULAE  FOR  AREA  QUESTIONS

 

 

FUNDAMENTAL CONCEPTS :

I. Results on Triangles:

1. Sum of the angles of  a triangle is 180o

2. The sum of any two sides of a triangle is greater than the third side.

3. Pythagoras Theorem : In a right - angled triangle,

Hypotenuse2=Base2+Height2

4. The line joining the mid-point of a side of a triangle to the opposite vertex is called the median.

5. The point where the three medians of a triangle meet, is called Centroid. The centroid divides each of the medians in the ratio 2 : 1.

6. In an Isosceles triangle, the altitude from the vertex bisects the base.

7. The median of a triangle divides it into two triangles of the same area.

8. The area of the triangle formed by joining the mid-points of the sides of a given triangle is one-fourth of the area of the given triangle.

 

II.Results on Quadrilaterals :


1. The diagonals of a parallelogram bisect each other

2. Each diagonal of a parallelogram divides it into two triangles of the same area.

3. The diagonals of a rectangle are equal and bisect each other.

4. The diagonals of a square are equal and bisect each other at right angles

5. The diagonals of a rhombus are unequal and bisect each other at right angles

6. A parallelogram and a rectangle on the same base and between the same parallels are equal in area.

7. Of all the parallelogram of given sides, the parallelogram which is a rectangle has the greatest area.

 

IMPORTANT FORMULAE

I. 

1. Area of a rectangle = (length x Breadth)

Length =AreaBreadth  and  Breadth=AreaLength

2. Perimeter of a rectangle = 2( length + Breadth)

 

 

II. Area of square = side2=12diagonal2 

 

III. Area of 4 walls of a room = 2(Length + Breadth) x Height

 

 

IV.

1. Area of a triangle =12×base×height

2. Area of a triangle = s(s-a)(s-b)(s-c), where a, b, c are the sides of the triangle and s=12a+b+c

3. Area of an equilateral triangle =34×side2

4. Radius of incircle of an equilateral triangle of side a=a23

5. Radius of circumcircle of an equilateral triangle of side a=a3

6. Radius of incircle of a triangle of area  and semi-perimeter s=s

 

 

V.

1. Area of a parallelogram = (Base x Height)

2. Area of a rhombus = 12×Product of diagonals

3. Area of a trapezium = 12×(sum of parallel sides)×distance between them

    

 

VI.

1. Area of a cicle = πR2, where R is the radius.

2. Circumference of a circle = 2πR.

3. Length of an arc = 2πRθ360, where θ is the central angle.

4. Area of a sector = 12arc×R=πR2θ360 

 

VII.

1. Area of a semi-circle = πR22

2. Circumference of a semi - circle = πR

Q:

The length of a rectangle is 10 cm more than the breadth. Find the diagonal length of rectangle if perimeter is 44 cm ?

A) 12.50 cm B) 14.21 cm
C) 15.98 cm D) 17.08 cm
 
Answer & Explanation Answer: D) 17.08 cm

Explanation:

Let the length of the rectangle = L cm

 

Then the breadth of the rectangle = (L - 10) cm

 

Perimeter of a rectangle = 2(L + B) cm

 

=> 44 = 2(L + L - 10)

 

=> 44 = 4L - 20

 

=> 4L = 64

 

=> L = 16 cm

 

=> B = L - 10 = 6 cm

 

Diagonal = L2+B2 = 162+62 = 17.08 cm

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11 5254
Q:

The area of a square is equal to the area of a rectangle. The length of the rectangle is 5 cm more than a side of the square and its breadth is 3 cm less than the side of the square. What is the perimeter of the rectangle ? 

A) 15 cm B) 18 cm
C) 34 cm D) 26 cm
 
Answer & Explanation Answer: C) 34 cm

Explanation:

Let the side of the square be 's' cm

 

length of rectangle = (s+5) cm

 

breadth of rectangle = (s-3)cm

 

(s+5) (s-3) = 

 

s2 - 5s - 3s - 15 = s2 

 

2s = 15

 

Perimeter of rectangle = 2(L+B) = 2(s+5 + s–3) = 2(2s + 2)

 

= 2(15 + 2) = 34 cm 

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28 5237
Q:

The length and the breadth of rectangular field are in the ratio of 8 : 7. If charges of the painting the boundary of rectangle is at Rs. 10 per meter is Rs. 3000. What is the area of rectangular plot?

A) 5600 sq.m B) 1400 sq. m
C) 4400 sq.m D) 3600 sq.m
 
Answer & Explanation Answer: A) 5600 sq.m

Explanation:

Perimeter of the rectangle is given by 3000/10 = 300 mts

But we know,

The Perimeter of the rectangle = 2(l + b)

Now,

2(8x + 7x) = 300

30x = 300

x = 10

Required, Area of rectangle = 8x x 7x = 56 x 100 = 5600 sq. mts.

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19 4806
Q:

In a rectangle, length is three times its breadth. If the length and the breadth of the rectangle are increased by 30% and 100% respectively, then its perimeter increases by

A) 40/3% B) 20%
C) 25% D) 27%
 
Answer & Explanation Answer: C) 25%

Explanation:
Let the breadth of the rectangle = x
Length of the the rectangle will be = 3 times of breadth = 3x
So the initial perimeter = 2(length + breadth) = 2(x + 3x) = 8x
New breadth after increase = x + 10x/100 = 1.1x
New length after increase = 3x + 30*3x/100 = 3.9x
New perimeter = 2(1.1x + 3.9x) = 10x
Percentage change in perimeter = ( 10x-8x)*100/8x = 25%
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10 4452
Q:

XYZ is right angled at Y. If mZ = 60°, then find the value of (cotX - 1/3).

A) (3√3-1)/3 B) (2√3-√6)/2√2
C) -5/3 D) (2-√3)/2√3
 
Answer & Explanation Answer: A) (3√3-1)/3

Explanation:
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0 4350
Q:

The perimeter of a rectangle whose length is 6 m more than its breadth is 84 m. What will be the area of the rectangle?

A) 333 sq.mts B) 330 sq.mts
C) 362 sq.mts D) 432 sq.mts
 
Answer & Explanation Answer: D) 432 sq.mts

Explanation:

Let the breadth of the rectangle = b mts

Then Length of the rectangle = b + 6 mts

Given perimeter = 84 mts

2(L + B) = 84 mts

2(b+6 + b) = 84

2(2b + 6) = 84

4b + 12 = 84

4b = 84 - 12

4b = 72

b = 18 mts

=> Length = b + 6 = 18 + 6 = 24 mts

 

Now, required Area of the rectangle = L x B = 24 x 18 = 432 sq. mts

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20 4276
Q:

Three medians AD, BE and CF of ΔABC intersect at G; Area of ΔABC is 36 sq cm. Then the area of ΔCGE is

A) 12 sq cm B) 6 sq cm
C) 9 sq cm D) 18 sq cm
 
Answer & Explanation Answer: B) 6 sq cm

Explanation:
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3 3922
Q:

Find the area of the trapezium, whose parallel sides are 12 cm and 10 cm, and distance between the parallel sides is 14 cm?

A) 121 sq.com B) 154 sq.com
C) 186 sq.com D) 164 sq.com
 
Answer & Explanation Answer: B) 154 sq.com

Explanation:

We know that, 

Area of trapezium = 1/2 x (Sum of parallel sides) x (Distance between Parallel sides)

= 1/2 x (12 + 10) x 14

= 22 x 14/2

= 22 x 7

= 154 sq. cm

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23 3582