FACTS  AND  FORMULAE  FOR  AREA  QUESTIONS

 

 

FUNDAMENTAL CONCEPTS :

I. Results on Triangles:

1. Sum of the angles of  a triangle is 180o

2. The sum of any two sides of a triangle is greater than the third side.

3. Pythagoras Theorem : In a right - angled triangle,

Hypotenuse2=Base2+Height2

4. The line joining the mid-point of a side of a triangle to the opposite vertex is called the median.

5. The point where the three medians of a triangle meet, is called Centroid. The centroid divides each of the medians in the ratio 2 : 1.

6. In an Isosceles triangle, the altitude from the vertex bisects the base.

7. The median of a triangle divides it into two triangles of the same area.

8. The area of the triangle formed by joining the mid-points of the sides of a given triangle is one-fourth of the area of the given triangle.

 

II.Results on Quadrilaterals :


1. The diagonals of a parallelogram bisect each other

2. Each diagonal of a parallelogram divides it into two triangles of the same area.

3. The diagonals of a rectangle are equal and bisect each other.

4. The diagonals of a square are equal and bisect each other at right angles

5. The diagonals of a rhombus are unequal and bisect each other at right angles

6. A parallelogram and a rectangle on the same base and between the same parallels are equal in area.

7. Of all the parallelogram of given sides, the parallelogram which is a rectangle has the greatest area.

 

IMPORTANT FORMULAE

I. 

1. Area of a rectangle = (length x Breadth)

Length =AreaBreadth  and  Breadth=AreaLength

2. Perimeter of a rectangle = 2( length + Breadth)

 

 

II. Area of square = side2=12diagonal2 

 

III. Area of 4 walls of a room = 2(Length + Breadth) x Height

 

 

IV.

1. Area of a triangle =12×base×height

2. Area of a triangle = s(s-a)(s-b)(s-c), where a, b, c are the sides of the triangle and s=12a+b+c

3. Area of an equilateral triangle =34×side2

4. Radius of incircle of an equilateral triangle of side a=a23

5. Radius of circumcircle of an equilateral triangle of side a=a3

6. Radius of incircle of a triangle of area  and semi-perimeter s=s

 

 

V.

1. Area of a parallelogram = (Base x Height)

2. Area of a rhombus = 12×Product of diagonals

3. Area of a trapezium = 12×(sum of parallel sides)×distance between them

    

 

VI.

1. Area of a cicle = πR2, where R is the radius.

2. Circumference of a circle = 2πR.

3. Length of an arc = 2πRθ360, where θ is the central angle.

4. Area of a sector = 12arc×R=πR2θ360 

 

VII.

1. Area of a semi-circle = πR22

2. Circumference of a semi - circle = πR

Q:

In the given figure, if  QR/XY = 14/9 and PY = 18 cm, then what is the value (in cm) of PQ?

 

 

A) 28 B) 18
C) 21 D) 24
 
Answer & Explanation Answer: A) 28

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Q:

If S is the midpoint of a straight line PQ and R is a point different from S, such that PR =RQ, then

 

A) ∠PRS = 90° B) ∠QRS = 90°
C) ∠PSR = 90° D) ∠QSR = 90°
 
Answer & Explanation Answer: C) ∠PSR = 90°

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Q:

Which of the following combination of sides results in the formation of obtuse angled triangle?

 

A) 6,7,13   B)  5, 6, 8  
C)  4, 5, 6   D)  None of these
 
Answer & Explanation Answer: B)  5, 6, 8  

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Q:

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: C) 3

Explanation:

Area of the park = (60 x 40) = 2400m2

Area of the lawn = 2109m2 

Area of the crossroads = (2400 - 2109) = 291m2 

Let the width of the road be x metres. Then,

60x+40x-X2=291 

x2-100x+291=0 

  (x - 97)(x - 3) = 0
   x = 3.

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86 80631
Q:

If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.

A) 110 B) 120
C) 130 D) 140
 
Answer & Explanation Answer: B) 120

Explanation:

let length = x and breadth = y then  

2(x+y) = 46         =>   x+y = 23  

x²+y² = 17² = 289  

now (x+y)² = 23² 

=> x²+y²+2xy= 529 

=> 289+ 2xy = 529

=> xy = 120  

area = xy = 120 sq.cm

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287 79434
Q:

The ratio of the areas of a square and a regular hexagon, both inscribed in a circle is?

 

A) 4 : 3√3 B) 1 : √3
C) 3√3 : 2 D) 2 : 3
 
Answer & Explanation Answer: A) 4 : 3√3

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Q:

∆ABC is right angled at B. If cosA = 8/17, then what is the value of cotC ?

 

A)  15/8 B) 15/17
C)  8/17 D) 17/15
 
Answer & Explanation Answer: A)  15/8

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Q:

If the diameter of a circle is 28 cm, then what will be its circumference (in cm)?

 

A) 88 B) 176
C) 35 D) 70
 
Answer & Explanation Answer: A) 88

Explanation:
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