# Bar Charts Questions

**1. Answer : 2**

**Explanation : **Productivity = Total production/area of Agr.land

Productivity of UP = [ (35000+30000+25000) / (30/100) ] = 300000

Productivity of MP = [ (30000+37500+27500) / (25/100) ] = 380000

Productivity of Bihar = [ (22500+27500+25000) / (20/100) ] = 375000

Productivity of Odisha = [ (22500+15000+10000) / (5/100) ]= 950000

Productivity of Haryana = [ (30000+25000+35000) / (8/100) ] = 1125000

Productivity of Punjab = [ (40000+35000+30000) / (12/100) ] = 875000

The Productivity of Haryana is the maximum.

**2. Answer : 5**

**Explanation : **Production of Punjab is maximum = 105000 tonnes

**3. Answer : 3**

**Explanation : **Production of Wheat in Punjab = 40000 tones

Production of Maize in Odisha = 10000 tones

Required % = (40000 - 10000)/100 = 300%

**4. Answer : 4**

**Explanation : **The ratio of prodution of Rice in Bihar to the production of Wheat in Haryana = 25000 tonnes : 25000 tonnes = 1 : 1

**5. Answer : 1**

**Explanation : **Income of MP from export of 40% of Rice at the rate of Rs.30 per kg = Rs.39crore

Income of UP from export of 30% of Rice at the rate of Rs.32 per kg = Rs.28.8 crore

Required ratio = 39 : 28.8 = 390 : 288 = 65 : 48

**1. ANSWER : 2**

**Explanation - **Compare the respective pass percentage for three years : 2000, 2001 and 2002

= (140 x 100)/170 < (150 x 100)/180 and (150 x 100)/180 > (160 x 100)/200

= 82.35% < 83.33% and 83.33% > 80%

**2. ANSWER : 3**

**Explanation - **Total percentage of students who succeeded in at least one of three exams in 2000 = (140 x 100)/170= 82.35 %

**3. ANSWER : 2**

**Explanation - **Total percentage increase in the number of students in 2002 over 2000 is = (30 x 100)/170 =17.64 %

**4. ANSWER : 4**

**Explanation - ** Total percentage of students who cleared CAT in 2000 =(20 x 100)/170 = 11.76 %

**1. Answer : 4**

**Explanation :** The water level of River-C in September = 184 and water level of River-B in June = 202

Required ratio = 184 : 202 => 92 : 101

**2. Answer : 2**

**3. Answer : 3**

**Explanation :** Average water level of River-A in all months =$\frac{196+205+230+212}{4}$= 210.75 m

**4. Answer : 4**

**5. Answer : 3**

**Explanation :** Water level of River-A in July after decreasing =$205\times \frac{80}{100}$ = 41 x 4 = 164m

**1. Answer : 4**

**Explanation :** Required Percentage =$\frac{100-50}{50}\times 100$= 100%

**2. Answer : 4**

**Explanation :** The average production of P = $\frac{60+90+50+100+80}{5}$= 76

The average production of Q =$\frac{50+70+70+80+100}{5}$ = 74

The average production of R = $\frac{70+80+90+70+70}{5}$ = 76

Maximum average production = P and R both

**3. Answer : 2**

**Explanation :** The percentage rise in 2010 =$\frac{70-50}{50}\times 100$ = 40%

The percentage rise in 2011 = $\frac{70-70}{70}\times 100$= 0%

The percentage rise in 2012 = $\frac{80-70}{70}\times 100$= 14.28%

The percentage rise in 2013 =$\frac{100-80}{80}\times 100$ =25%

**4. Answer : 2**

**Explanation :** The percentage of production of Company R to production of Company Q

in 2009 =$\frac{70}{50}\times 100$ = 140

in 2010 =$\frac{80}{70}\times 100$ = 114.28

in 2011 =$\frac{90}{70}\times 100$ = 128.57

in 2012 = $\frac{70}{80}\times 100$= 87.5

in 2013 = $\frac{70}{100}\times 100$= 70

**5. Answer : 1**

**Explanation :** Average production of company P during the years 2011 to 2013 =$\frac{50+100+80}{3}$ = $\frac{230}{3}$

Average production of company Q during the years 2011 to 2013 =$\frac{70+80+100}{3}$ = $\frac{250}{3}$

Required ratio = 23 : 25

**Answer 1) **

1/3 x (54 x 150 + 60 x 300 + 36 x 450)

= 1/3 x 42300

**= 14100.**

**Answer 2)**

Required ratio of chairs = $\frac{\mathbf{64}\mathbf{}\mathbf{x}\mathbf{}\mathbf{450}\mathbf{}\mathbf{+}\mathbf{}\mathbf{56}\mathbf{}\mathbf{x}\mathbf{}\mathbf{500}}{\mathbf{36}\mathbf{}\mathbf{x}\mathbf{}\mathbf{450}\mathbf{}\mathbf{+}\mathbf{}\mathbf{44}\mathbf{}\mathbf{x}\mathbf{}\mathbf{500}}$

= 56800/38200

**= 284/191.**

**Answer 3)**

Required number of chairs = $\frac{\mathbf{3}}{\mathbf{5}}\mathbf{}\mathbf{x}\mathbf{}\frac{\mathbf{12}}{\mathbf{100}}\mathbf{}\mathbf{x}\mathbf{}\mathbf{50000}$**= 3600.**