6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

From a container of wine, a thief has stolen 15 liters of wine and replaced it with same quantity of water.He again repeated the same process. Thus in three attempts the ratio of wine and water became 343:169. The initial amount of wine in the container was:

A) 75 liters	B) 100 liters
C) 150 liters	D) 120 liters

Answer & Explanation Answer: D) 120 liters

Explanation:

$\frac{W i n e (l e f t)}{W a t e r (a d d e d)} = \frac{343}{169}$

It means $\frac{W i n e (l e f t)}{W i n e (i n i t i a l a m o u n t)} = \frac{343}{512}$ $[∵ 343 + 169 = 512]$

Thus ,

$343 x = 512 x {(1 - \frac{15}{K})}^{3}$

$\Rightarrow \frac{343}{512} = {(\frac{7}{8})}^{3} = {(1 - \frac{15}{k})}^{3}$

=> K = 120

Thus the initial amount of wine was 120 liters.

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Filed Under: Alligation or Mixture

40 28910

Q:

Consider the following statements:

1) The perimeter of a triangle is greater than the sum of its three medinas.

2) In any triangle ABC, if D is any point on BC, then AB + BC + CA > 2AD.

Which of the above statements is/are correct?

A) 1 only	B) 2 only
C) Both 1 and 2	D) Neither 1 nor 2

Answer & Explanation Answer: C) Both 1 and 2

Explanation:

Let ABC be the triangle and D. E and F are midpoints of BC, CA and AB respectively.

Recall that the sum of two sides of a triangle is greater than twice the median bisecting the third side,(Theorem to be remembered)

Hence in ΔABD, AD is a median

⇒

AB + AC > 2(AD)

Similarly, we get

BC + AC > 2CF

BC + AB > 2BE

On adding the above inequations, we get

(AB + AC) + (BC + AC) + (BC + AB )> 2AD + 2CD + 2BE

2(AB + BC + AC) > 2(AD + BE + CF)

∴

AB + BC + AC > AD + BE +CF

2.

To prove: AB + BC + CA > 2AD

Construction: AD is joined

Proof: In triangle ABD,

AB + BD > AD [because, the sum of any two sides of a triangle is always greater than the

third side]

----

1

In triangle ADC,

AC + DC > AD [because, the sum of any two

sides of a tri

angle is always greater than the

third side]

----

2

Adding 1 and 2 we get,

AB + BD + AC + DC > AD + AD

=> AB + (BD + DC) + AC > 2AD

=> AB + BC + AC > 2AD

Hence proved

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

1 28840

Q:

The diameter of the driving wheel of a bus is 140 cm. How many revolution, per minute must the wheel make in order to keep a speed of 66 kmph ?

A) 150	B) 250
C) 350	D) 550

Answer & Explanation Answer: B) 250

Explanation:

Circumference = No.of revolutions * Distance covered

Distance to be covered in 1 min. = (66 X1000)/60 m = 1100 m.
Circumference of the wheel = 2 x (22/7) x 0.70 m = 4.4 m.
Number of revolutions per min. =(1100/4.4) = 250.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

47 28840

Q:

For the figure given below, find the angle OAB (in degrees).

A) 25	B) 50
C) 75	D) 90

Answer & Explanation Answer: C) 75

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams

1 28827

Q:

If side of a square is increased by 60%, then what will be the percentage increase in its area?

A) 156	B) 120
C) 126	D) 132

Answer & Explanation Answer: A) 156

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams

1 28823

Q:

The second statement is the ____ of the first.

$1 . P \Rightarrow Q 2 . ~ Q \Rightarrow ~ P$

A) Converse	B) Inverse
C) Contrapositive	D) Contradiction

Answer & Explanation Answer: C) Contrapositive

Explanation:

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Filed Under: Probability
Exam Prep: Bank Exams

3 28795

Q:

15% of 60 is 45% of __

A) 20	B) 30
C) 180	D) 40

Answer & Explanation Answer: A) 20

Explanation:

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Filed Under: Percentage
Exam Prep: Bank Exams

4 28771

Q:

A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?

A) 10/21	B) 11/21
C) 1/2	D) 2/7

Answer & Explanation Answer: A) 10/21

Explanation:

Total number of balls = (2 + 3 + 2) = 7.

Let S be the sample space.

Then, n(S) = Number of ways of drawing 2 balls out of 7 = $7 C_{2}$ = 21

Let E = Event of drawing 2 balls, none of which is blue.

n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls = $5 C_{2}$ = 10

Therefore, P(E) = n(E)/n(S) = 10/ 21.

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Filed Under: Probability

37 28766

Quantitative Aptitude - Arithmetic Ability Questions

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