Quantitative Aptitude - Arithmetic Ability Questions

Q:

If 76 is divided into four parts proportional to 7, 5, 3, 4, then the smallest part is:

A) 12 B) 15
C) 16 D) 19
 
Answer & Explanation Answer: A) 12

Explanation:

Given ratio = 7 : 5 : 3 : 4, Sum of ratio terms = 19.

Smallest part =  (76*3/19)  = 12

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Filed Under: Ratios and Proportions

73 29446
Q:

Read the data given and answer the following questions

 

In a class of 60 students:

 

42 like Maths,

32 like English,

12 like neither Maths nor English

 

How many students like both Maths and English?

A) 28 B) 26
C) 16 D) 12
 
Answer & Explanation Answer: B) 26

Explanation:
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Filed Under: Percentage
Exam Prep: Bank Exams

1 29398
Q:

The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is :

A) Rs. 560 B) Rs. 530
C) Rs. 500 D) Rs. 514
 
Answer & Explanation Answer: C) Rs. 500

Explanation:

110% of S.P. = Rs. 616

S.P. = (616 x 100)/110 = Rs. 560

C.P = (110 x 560)/112 = Rs. 500

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

65 29345
Q:

Entry fee in an exhibition was Rs. 1. Later, this was reduced by 25% which increased the sale by 20%. The percentage increase in the number of visitors is :

A) 20 % B) 40 %
C) 60 % D) 80 %
 
Answer & Explanation Answer: C) 60 %

Explanation:

Let the total original sale be Rs. 100. Then, original number of visitors = 100.

New number of visitors  =  120/0.75 = 160.

Increase % = 60 %.

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Filed Under: Percentage

95 29240
Q:

The average temperature of the town in the first four days of a month was 58 degrees. The average for the second, third, fourth and fifth days was 60 degrees. If the temperatures of the first and fifth days were in the ratio 7 : 8, then what is the temperature on the fifth day ?

A) 62 degrees B) 64 degrees
C) 65 degrees D) 66 degrees
 
Answer & Explanation Answer: B) 64 degrees

Explanation:

Sum of temperatures on 1st, 2nd, 3rd and 4th days = (58 * 4) = 232 degrees ... (1)

Sum of temperatures on 2nd, 3rd, 4th and 5th days - (60 * 4) = 240 degrees  ....(2)

Subtracting (1) From (2), we get :

Temp, on 5th day  - Temp on 1st day  = 8 degrees.

Let the temperatures on 1st and 5th days be 7x and 8x degrees respectively.

Then, 8x - 7x = 8 or x = 8.

Temperature on the 5th day = 8x = 64 degrees.

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Filed Under: Average

56 29227
Q:

A and B can do a piece of work in 40 and 50 days. If they work at it an alternate days with A beginning in how many days, the work will be finished ?

Answer

(A+B)'s two days work = 140+150=9200 


 


Evidently, the work done by A and B duing 22 pairs of days 


 


 i.e in 44 days = 22×9200=198200 


 


Remaining work = 1-198200= 1/100


 


 Now on 45th day A will have the turn to do 1/100 of the work and this work A will do in 40×1100=25


 


 Therefore,  Total time taken = 4425daya

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Subject: Time and Work
Job Role: Bank PO

72 29221
Q:

Find the appropriate relation for quantity 1 and quantity 2 in the following question:

Quantity I: the unit digit in (6817)754

Quantity II: the unit digit in (365×659×771)

A) Quantity I > Quantity II B) Quantity I < Quantity II
C) Quantity I ≥ Quantity II D) Quantity I ≤ Quantity II
 
Answer & Explanation Answer: A) Quantity I > Quantity II

Explanation:
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1 29220
Q:

The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.

A) B=900;H=300 B) B=300;H=900
C) B=600;H=700 D) B=500;H=900
 
Answer & Explanation Answer: A) B=900;H=300

Explanation:

Area of the field = Total cost/rate = (333.18/25.6) = 13.5 hectares
13.5*10000m2=135000m2 
Let altitude = x metres  and  base = 3x metres.
Then, 12*3x*x=135000x2=90000x=300 

Base = 900 m and Altitude = 300 m.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

62 29212